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alexandr402 [8]
3 years ago
10

A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an

d C, as shown below:

Mathematics
2 answers:
Viktor [21]3 years ago
8 0

Let base of walls be D and E respectively

Now

  • In∆AEC

\\ \sf\longmapsto tan45°=\dfrac{80}{AE}

\\ \sf\longmapsto AE=\dfrac{80}{tan45}

\\ \sf\longmapsto AE=\dfrac{80}{1}

\\ \sf\longmapsto AE=80m

  • In ∆ADC

\\ \sf\longmapsto cos60=\dfrac{AD}{40}

\\ \sf\longmapsto AD=0.5(40)

\\ \sf\longmapsto AD=20m

Now distance between walls=

  • AE+AD=80+20=100m
MissTica3 years ago
5 0

A source of laser light is at point A on the ground between two parallel walls. The walls are perpendicular to the ground. AB is a ray of light which strikes the wall on the left at point B which is 60 meters above the ground. AC is a ray of light which strikes the wall on the right at point C which is 40 m above the ground. The ray AB makes an angle of 60 degrees with the ground. The ray AC makes an angle of 30 degrees with the ground.

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