Question

• a woman is seven times as old as her son. after five years she will be four times as old as her son. what are the present ages of the mother and son?
Answer asap!​

Answer 1

Let

• present age of son=y
• present age of mother=7y

After 5years

• age of son=y+5
• age of mother=7y+5

ATQ

$\\ \sf\longmapsto 7y+5=4(y+5)$

$\\ \sf\longmapsto 7y+5=4y+20$

$\\ \sf\longmapsto 7y-4y=20-5$

$\\ \sf\longmapsto 3y=15$

$\\ \sf\longmapsto y=5$

$\\ \sf\longmapsto 7y=5(7)=35$

• Present age of son=5yrs
• Present age of mother=35yrs

Answer 2

Answer:

35 and 5

Step-by-step explanation:

let the son's age be x then mother's age is 7x

In 5 years

son's age = x + 5 , mothers age is 7x + 5 and

7x + 5 = 4(x + 5)

7x + 5 = 4x + 20 ( subtract 4x from both sides )

3x + 5 = 20 ( subtract 5 from both sides )

3x = 15 ( divide both sides by 3 )

x = 5

son's age is 5

mother's age is 7x = 7 × 5 = 35