0.45 0.35 and .45 then you just multiply all of them and its gives you .071
<u><em>Tell Me If Somethings wrong with my answer! </em></u>
You say that there is uniform acceleration so:
vf-vi=at (final velocity minus initial velocity is equal to acceleration times time)
We know vf, vi, and t so we can solve for acceleration:
24-12=a10
12=10a
a=1.2
That is the acceleration, we will need to integrate with respect to time twice...
v=⌠a dt
v=at+vi , we know a=1.2m/s^2 and vi=12m/s
v=1.2t+12,
x=⌠1.2t+12 dt
x=1.2t^2/2+12t+xo, we can just let xo=0 for this problem...
x(t)=0.6t^2+12t
Now we know that this acceleration lasts for 10 seconds so the distance traveled in that time is:
x(10)=0.6(10^2)+12(10)
x(10)=60+120
x(10)=180 meters
Answer:
The answer is:
12 ( y+ 
)
this suits perfectly the description
Answer: x = 65.63
Explanation:
We have, 64% × x = 42 or, 64/100 × x = 42
Multiplying both sides by 100 and dividing both sides by 64, we have x = 42 × 100 64
x = 65.63
