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maks197457 [2]
2 years ago
11

The height of a right square pyramid is multiplied by 10, but the area of the base is unchanged. By what factor is the volume of

the pyramid multiplied?
a 10⁰
b 10¹
c 10²
d 10³​
Mathematics
1 answer:
pshichka [43]2 years ago
5 0

Answer:

  b 10¹

Step-by-step explanation:

Consider the volume formula:

  V = 1/3Bh . . . . B is the base area and h is the height

Replacing h by 10h gives ...

  V' = 1/3B(10h) = 10(1/3Bh) = 10V

The volume is multiplied by 10 = 10¹.

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...................can someone plz help?
galben [10]

Answer:

2.5 feet

Step-by-step explanation:

65- 53 3/4 = 11.25

11.25= 2.5 per year

hope this helps!

8 0
3 years ago
Jason is building a 1 : 180 scale model of a real castle. his model has a rectangular base that is 3 feet wide and 4 feet long.w
balu736 [363]
The area of the actual castle would be 388,800 sq. ft.

We would multiply each of the sides of the scale model both by 180 to find the side lengths of the actual castle.

So...
180 x 4 = 720
180 x 3 = 540

If Area is equal to Length Times Width, all thats left to do is to multiply the two sides together.

720 x 540 = 388,800

Hope this helped! :D
3 0
2 years ago
WILL MARK U AS BRAINLIEST!!! Evaluate the following expressions given the functions below:
Scorpion4ik [409]

sorry that was a mistake tee hee

7 0
3 years ago
In this truss bridge, AAOB ABDC. AO=5 meters, BD=10 meters, AB=5 meters. What is the length of BC? A. 5 m B. 8 m C. 10 m D. 15 m
Olenka [21]

Consider \Delta AOB\cong \Delta BDC.

Given:

\Delta AOB\cong \Delta BDC, AO=5\ m,BD=10\ m, AB=5\ m.

To find:

The length of BC.

Solution:

We have,

\Delta AOB\cong \Delta BDC

We know that the corresponding parts of congruent triangles are congruent (CPCTC).

AB=BC                   (CPCTC)

5\ m=BC

The length of BC is 5 m. Therefore, the correct option is A.

5 0
2 years ago
The length of a rectangle is 5 inches shorter than double its width. The perimeter of the rectangle is 192 inches. Write a two-s
alukav5142 [94]

Answer:

Step-by-step explanation:

Givens

Let the width = x

Let the length = x + 5

Equation

2w + 2W = P

Solution

2x + 2(x + 5) = 192                  Remove the brackets    <=== Answer

2x + 2x + 10 = 192                  Combine like terms

4x + 10 = 192                          Subtract 10 from both sides

4x = 192 - 10                        

4x = 182                                 Divide by 4

4x/4 = 182/4

x = 45.5

8 0
2 years ago
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