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leonid [27]
3 years ago
6

PLEASE HELP ASAP! WILL GIVE BRAINLIEST!

Mathematics
2 answers:
AURORKA [14]3 years ago
7 0

Answer:

The boundry line becomes dashed

The boundry line is transferred vertically

Step-by-step explanation:

Edge 2020

Sergeu [11.5K]3 years ago
4 0

Answer: The boundary line is translated vertically

Since the only thing changed is the +80, it is only affecting the y-intercept of the inequality or "c"

a = bx + c

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Can somebody help outtt ?? pleasee
OleMash [197]

Answer:

y=71

x=109

Step-by-step explanation:

7 0
3 years ago
One dozen eggs were purchased for $.89 how much do three eggs cost
boyakko [2]
I think and hope it is $ 267 because a dozen is 12

8 0
3 years ago
Read 2 more answers
0.199<br> to the nearest hundredth.
RideAnS [48]
0.20 would  be the answer.
The number places on a number go as follows starting at 0. and going to the right
ones, tenths, hundredth
This means that 0.00 is the hundredth place (the bolded 0). Since you round a 9 up one, this makes the 1 in the tenths place go to a 2 and the hundredth go to a 0

6 0
3 years ago
There is 5/6 of an apple pie left from dinner.Tomorrow,Victor plans to eat 1/6 of the pie that was left.How much of the whole pi
kow [346]

Answer:

1=2/3 reduced or 4/6 full

2=8/3


Step-by-step explanation:


4 0
3 years ago
Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,
MrRissso [65]

Answer:

4.82\cdot 10^{-4}

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

n-1=51

Therefore, the probability of drawing a three at the 2nd draw is

p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784

Then, at the third draw, the previous 2 cards are not replaced, so there are now

n-2=50

cards in the deck. So, the probability of drawing a jack is

p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08

Therefore, the total probability of drawing an ace, a three and then a jack is:

p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}

4 0
3 years ago
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