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kvv77 [185]
3 years ago
8

Round 288 to the nearest tenth

Mathematics
1 answer:
cricket20 [7]3 years ago
6 0
290

hopefully i could help ;)

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Find the value of x.<br> 3<br> X<br> x = [?]
DedPeter [7]
I think it would be 2 because it looks like 6 is the total and 3 is a side number so if you were to multiply 3 times 2 it would be 6. I hope this is correct!
3 0
3 years ago
What is the solution of ?<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20x-7%3D%5Cfrac%7B3%7D%7B4%7D%20x%2B14" id="Tex
Nonamiya [84]

Combine the terms by multiplying into a single fraction.

\bf{\dfrac{5}{2}x-7=\dfrac{3}{4}x+14   }

Find the common denominator.

\bf{\dfrac{5x}{2}-7=\dfrac{3}{4}x+14   }

Combine fractions with the lowest common denominator.

\bf{\dfrac{5x(-7)}{2}=\dfrac{3}{4}x+14   }

Multiply the numbers.

\bf{\dfrac{5x-14}{2}=\dfrac{3}{4}x+14   }

Combine the multiplied terms into a single fraction

\bf{\dfrac{5x-14}{2}=\dfrac{3x}{4}+14   }

Find the common denominator.

\bf{\dfrac{5x-14}{2}=\dfrac{3x}{4}+\dfrac{4\cdot14}{4}    }

Combine fractions with the lowest common denominator.

\bf{\dfrac{5x-14}{2}=\dfrac{3x+4\cdot14}{4}   }

Multiply the numbers.

\bf{\dfrac{5x-14}{2}=\dfrac{3x+56}{4}   }

Eliminate the denominators of the fractions.

\bf{4\cdot\dfrac{5x-14}{2}=4\cdot\dfrac{3x+56}{4}   }

Cancel the multiplied terms that are in the denominator.

\bf{2(5x-14)=3x+56}

To distribute.

\bf{10x-28=3x+56 }

Add 28 to both sides.

\bf{10x-28+28=3x+56+28 }

Simplify

\bf{10x=3x+84 }

Subtract 3x from both sides.

\bf{10x-3x=3x+84-3x }

Simplify

\bf{7x=84 }

Divide both sides by the same factor.

\bf{x=\dfrac{84}{7} }

Simplify

\bf{x=12 \ \ \ === > \ \ \ Answer}

↓

<h3>Verification</h3>

Let x=12.

  1. \bf{\dfrac{5}{2}\times12-7=\dfrac{3}{4}\times12+14   }
  2. \bf{\dfrac{5\times12}{2}-7=\dfrac{3}{4}\times12+14   }
  3. \bf{\dfrac{60}{2}-7=\dfrac{3}{4}\times12+14   }
  4. \bf{30-7=\dfrac{3}{4}\times12+14   }
  5. \bf{30-7=\dfrac{3\times12}{4}+14   }
  6. \bf{30-7=\dfrac{36}{4}+14   }
  7. \bf{30-7=9+14   }
  8. \bf{23=9+14 }
  9. \bf{23=23}

Checked ✅

3 0
2 years ago
you are attempting to guess a 3 digit number and have the following information. there are no 0s the number is even. the sum of
ss7ja [257]

The 3-digit number is 132

<h3>How to determine the 3-digit number?</h3>

The given parameters are:

  • Number of digits = 3
  • Sum of digits = 6
  • No 0s in the number
  • No repeated digit

The first highlight above implies that the number can be any of 100 to 999

The other highlights imply that the no digit can appear repeatedly, the highest digit in the number is 3, and the number must end with 2.

So, we have:

X32

The first digit is the smallest.

1 is smaller than 3 and 2.

So, we have

132

Hence, the 3-digit number is 132

Read more about digits and numbers at:

brainly.com/question/26856218

#SPJ1

7 0
2 years ago
In a particular country, there are two types of currency: Kabuls and Carumpts. 8 Kabuls and 2 Carumpts are worth $61.70. 3 Kabul
Misha Larkins [42]

Answer:

Kabuls = 7.5

Carumpts= 0.85

Step-by-step explanation:

Let x represent the price of kabuls

Let y represent the price of carumpts

8x + 2y= 61.70......equation 1

3x + 10y= 31.........equation 2

Multiply equation 1 by 3 and equation 2 by 8

24x + 6y= 185.1

24x + 80y= 248

-74y = -62.9

y= 62.9/74

y= 0.85

Substitute 0.85 for y in equation 1

8x + 2(0.85) = 61.70

8x + 1.7= 61.70

8x = 61.70-1.7

8x = 60

x= 60/8

x= 7.5

Hence the dollar value for kabuls is 7.5 and carumpts is 0.85

3 0
3 years ago
Factor and solve the problems in the photo ……….. pleaseeeee help i haven’t done algebra in 2 years
vladimir1956 [14]

Answer:

30. 2x²-x-1=0

or, 2x²-2x+x-1=0

or, 2x(x-1)+1(x-1)=0

or, (x-1)(2x+1)=0

so, x-1 = 0 or, x = 1

and 2x+1 = 0 or, 2x = -1 or, x = -1/2

so, x = 1 and 1/2

31. 3x²-14x=5

or, 3x²-14x-5=0

or, 3x²-15x+x-5=0

or, 3x(x-5)+1(x-5)=0

or, (x-5)(3x+1)=0

so, x-5=0 or, x=5

and 3x+1=0 or, 3x=-1 or, x=-1/3

so, x = 5 and -1/3

Answered by GAUTHMATH

5 0
3 years ago
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