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Vlad [161]
3 years ago
10

Match the width with the go given area.

Mathematics
1 answer:
LekaFEV [45]3 years ago
8 0

Hello!

<h2>Answer:</h2>

\boxed{ \bf 1.~l~=~9.25~cm;~A~=~55.5~cm^2~matches~with~the~last~option~w~=~6~cm.}

\boxed{ \bf 2.~l~=~7.5~cm;~A~=~48.75~cm^2~matches~with~the~second~option~w~=~6.5~cm.}

\boxed{ \bf 3.~l~=~5~cm;~A~=~44~cm^2~matches~with~the~third~option~w~=~8.8~cm.}

\boxed{ \bf 4.~l~=~5~cm;~A~=~31.25~cm^2~matches~with~the~first~option~w~=~6.25~cm.}

<h2>__________________________________</h2><h2>Explanation:</h2>

We already know that the formula for area of a rectangle is A = l × w.

Notice how the width and the length are being multiplied to find the area.

Well, to find the width, we must do the <em>opposite</em> of multiplication, which is division.

Since we already have the length, all we have to do is divide the area by the length for each of the questions.

1:

A = l × w

55.5 = 9.25 × w

\frac{55.5}{9.25} = 6

2:

A = l × w

48.75 = 7.5 × w

\frac{48.75}{7.5} = 6.5

3:

A = l × w

44 = 5 × w

\frac{44}{5} = 8.8

4:

A = l × w

31.25 = 5 × w

\frac{31.25}{5} = 6.25

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