Nth term of term 5 10 15 20 25

1 answer:

7 0

Answer:

Step-by-step explanation:

The sequence is a list of multiples of 5, starting with 5×1. The n-th multiple is 5n.

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alexandr402 [8]

Answer:

$\large\boxed{-c^2(3c-2)=-3c^3+2c^2}$

Step-by-step explanation:

$-c^2(3c-2)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\=(-c^2)(3c)+(-c^2)(-2)\\\\=-3c^3+2c^2$

7 0

3 years ago

nikklg [1K]

Hey there!

Firstly, you have to $\bold{simplify}$ each of the sides of your equation
$\bold{6-2p-p+9\downarrow}$
$\bold{6+(-2p)=p+9\downarrow}$
$\rightarrow\bold{-2p+6=p+9}$
Now that you have that portion out of the way, we could move on to our second step... which is to $\bold{subtract}$ by the value of $\bold{p}$ on each of your sides
$\bold{-2p+6-p-p+9-p\downarrow}$
$\rightarrow\bold{-3p+6-9}$ (you get this because we solve the particular equation we added above)
Thirdly, you have to $\bold{subtract}$ by the number $\bold{6}$ on each of your sides
$\bold{-3p+6-6=9-6\downarrow}$
$\bold{Cancel:6-6}$ because it equals to $\bold{0}$
$\bold{Keep:9-6}$ because it brings us closer and closer to the answer of $\bold{p}$
Fourthly, we have to $\bold{divide}$ by the number $\bold{-3}$ on each of your sides
$\bold{\frac{-3p}{-3}=\frac{3}{-3}}$
$\boxed{\boxed{\bold{Answer:p=-1}}}$ $\checkmark$