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2 years ago

12

For the following problem, y varies directly as x If y = 34 when x = 4 , find y when x is 3.

1 answer:

mote1985 [20]2 years ago

6 0

Answer:

Step-by-step explanation: plug in 3 for X and then solve

Give me 5 stars

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Please help pictures below!

qaws [65]

the frist one is 7the second one is 33

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3 years ago

The length of a rectangle is 4 meters less than twice the width. If the area of the rectangle is 286 square meters, find the di

zaharov [31]

Answer:

W = 13 meters, L = 22 meters

Step-by-step explanation:

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2 years ago

Simplify: 9 x 5 ( 2 x 4 )

amid [387]

Is it 360 or 53 I think it’s 360

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2 years ago

Read 2 more answers

A landscaping company sells 13 bushes and 4 trees for $616. Come up with an equation to describe this relationship. If trees cos

xxTIMURxx [149]

Answer:

Bushes cost $28

Step-by-step explanation:

WE have:-

4*63 + 13b = 616 where b = cost of one bush.

252 + 13b = 616

13b = 616 - 252 = 364

b = 364/13

b = 28 (answer)

6 0

3 years ago

Find the linear approximation of the function g(x) = 3 1 + x at a = 0. g(x) ≈ Correct: Your answer is correct. Use it to approxi

EleoNora [17]

Answer:

$3.296x+3$

2.835

3.330

Step-by-step explanation:

$g(x) = 3^{1+x}$

Let the linear approximation be L(x) at a = 0. This is given by

$L(x) = g(a) + g'(a)(x-a)$

$g'(x)$ is the derivative of $g(x)$ . To find this, we use the form

If $f(x) = a^x$ , then $f'(x) =a^x\ln a$

By doing this and applying chain rule for the power (which is a function of x), we have

$g'(x) = 3^{1+x}\ln 3$

Then

$g'(0) = 3^{1+0}\ln 3 = 3.296$

Also $g(0) = 3^{1+0} = 3$

Hence $L(x) = 3+(x-0)\times3.296 = 3.296x + 3$

For $3^{0.95}$ , $1+x = 0.95$ and $x=-0.05$

Using this in $L(x)$ ,

$3^{0.95} = 3.296(-0.05) + 3 = 2.835$

For $3^{1.1}$ , $1+x = 1.1$ and $x=0.1$

Using this in $L(x)$ ,

$3^{1.1} = 3.296(0.1) + 3 = 3.330$

7 0

3 years ago