1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Slav-nsk [51]
4 years ago
5

A roller coaster at an amusement park girls from the top of a tall hill to the bottom during this time of the roller coaster

Physics
1 answer:
Mrac [35]4 years ago
8 0

D), because the roller coaster it's falling, therefore, losing height, but gaining velocity

You might be interested in
A 25,000 kg traveling east collides with a 2,000 kg truck standing still on the tracks. After the collision the train and truck
Elis [28]

Answer:

24.084 m/s

Explanation:

From the law of conservation of linear momentum

Total momentum before collision equals to the total momentum after collision

Since momentum=mv where m is mass and v is velocity

M_{truck}V_{truck}=V_{common}*(M_{truck} +M_{standing}) where M_{truck} is the mass of the truck, V_{truck} is velocity of the truck, V_{common} is the common velocity of moving and standing truck after collision and M_{standing} is the mass of the standing truck

Making V_{truck} the subject we obtain

V_{truck}=\frac { V_{common}*(M_{truck} +M_{standing})}{M_{truck}}

Substituting M_{truck} as 25000 Kg, V_{common} as 22.3 m/s, M_{standing} as 2000 Kg we obtain

V_{truck}=\frac { 22.3 m/s *(25000 Kg +2000 Kg)}{25000}= 24.084 m/s

Therefore, assuming no friction and considering that after collision they still move eastwards hence common velocity and initial truck velocities are positive

The truck was moving at 24.084 m/s

3 0
3 years ago
Suppose a straight 1.00-mm-diameter copper wire could just "float" horizontally in air because of the force due to the Earth’s m
insens350 [35]

To solve this problem it is necessary to apply the concepts related to the Force since Newton's second law, as well as the concept of Electromagnetic Force. The relationship of the two equations will allow us to find the magnetic field through the geometric relations of density and volume.

F_{mag}= BIL

Where,

B = Magnetic Field

I = Current

L = Length

<em>Note: F_{mag}  is a direct adaptation of the vector relation F=q \times V \times B</em>

From Newton's second law we know that the relation of Strength and weight is determined as

F_g = mg

Where,

m = Mass

g = Gravitational Acceleration

For there to be balance the two forces must be equal therefore

F_{mag} = F_g

BIL = mg

Our values are given as,

Diameter (d) = 1.0mm = 1*10^{-3}m

Radius (r) = \frac{d}{2} = \frac{1*10^{-3}}{2} = 0.5*10^{-3}m

Magnetic Field (B) = 5.0*10^{-5} T

From the relationship of density another way of expressing mass would be

\rho = \frac{m}{V} \rightarrow m = \rho V

At the same time the volume ratio for a cylinder (the shape of the wire) would be

V = \pi r^2 L \rightarrow L =Length, r= Radius

Replacing this two expression at our first equation we have that:

BIL = mg

BIL = ( \rho V)g

BIL = ( \rho \pi r^2 L)g

Re-arrange to find I

I = \frac{( \rho \pi r^2 L)g}{BL}

I = \frac{( \rho \pi r^2 )g}{B}

We have for definition that the Density of copper is 8.9*10^3 Kg/m^3, gravity acceleration is 9.8m/s^2 and the values of magnetic field (B) and the radius were previously given, then:

I = \frac{( (8.9*10^3 ) \pi (0.5*10^{-3})^2 )(9.8)}{5.0*10^{-5}}

I = 1370.05A

The current is too high to be transported which would make the case not feasible.

8 0
3 years ago
A plane traveled for 3 hours at a velocity of 1200 km/hr North. What is the distance traveled?
Daniel [21]

Answer:

the answer is 3600 kilometers

4 0
3 years ago
A stunt pilot weighing 0.70 kN performs a vertical circular dive of radius 0.80 km.At the bottom of the dive, the pilot has a sp
Yuliya22 [10]

Answer:

 Force plane exert on pilot  = 4270 N

Explanation:

first convert radius and speed to ms

using formula from force we know that

mass = weight/ gravity =  700 N/ 9.8N/kg=  71.4 kg

Fc=  N-mg

N= Fc+ mg                  As Fc = mv²/R

N= mv²/R + mg

taking m common

N= m( v²/R +g)

   = 71.4( (200)²/ 800 + 9.8 )

 Force  = 4270 N

3 0
4 years ago
How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro's number of ele
konstantin123 [22]

Answer:

-1486 KJ

Explanation:

The work done by an electric field on a charged body is:

W = ΔV * q

where ΔV = change in voltage

q = total charge

The total charge of Avogadro's number of electrons is:

6.0221409 * 10^(23) * -1.6023 * 10^(-19) = -9.65 * 10^(4)

The change in voltage, ΔV, is:

9.20 - (6.90) = 15.4

Therefore, the work done is:

W = -9.65 * 10^(4) * 15.4 = -1.486 * 10^6 J = -1486 KJ

The negative sign means that the motion of the electrons is opposite the electrostatic force.

5 0
3 years ago
Other questions:
  • 10 POINTS will mark brainliest if correct
    8·1 answer
  • A monatomic ideal gas in equilibrium at a pressure of 3 kPa and a temperature of 300 K is initially confined in a volume of 1.3
    13·1 answer
  • Select all of the answers that apply.
    5·2 answers
  • A van slows down uniformly from 17 m/s to 0 m/s in 5 s. How far does it travel before stopping?
    6·1 answer
  • When does a skydiver achieve terminal velocity?
    7·1 answer
  • Match the theory to the statement that best describes it. 1. big bang. 2. steady state. 3.osscillating universe. 4. inflation Ch
    11·2 answers
  • The top of a swimming pool is at ground level. If the pool is 3.00 m deep, how far below ground level does the bottom of the poo
    8·1 answer
  • 8.
    12·1 answer
  • Help plzzzzzzz<br><br><br><br>-it's not physics I couldn't put science
    6·1 answer
  • A radar receiver indicates that a pulse return as an echo in 20 μs after it was sent. How far away is the reflecting object? (c
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!