Answer:
Player II should remove 14 coins from the heap of size 22.
Step-by-step explanation:
To properly answer this this question, we need to understand the principle and what it is exactly is being asked.
This question revolves round a game of Nim
What is a game of Nim: This is a strategic mathematical game whereby, two opposing sides or opponent take turns taking away objects from a load or piles. On each turn, a player remove at least an object and may remove any number of objects provided they all come from the same heap/pile.
Now, referring back to the question, we should first understand that:
22₂ = 1 0 1 1 0
19₂= 1 0 0 1 1
14₂= 0 1 1 1 0
11₂= 0 1 0 1 1
and also that the “bit sums” are all even, so this is a balanced game.
However, after Player I removes 6 coins from the heap of size 19, Player II should remove 14 coins from the heap of size 22.
Answer:
80
Step-by-step explanation:
25 percent is equal to 1/4
1/4 of 80 is 20
(368 points) / (32 games) = 11.5 points/game
(32 games) / (368 points) = 0.08696 game/point
Answer:
12.38
Step-by-step explanation:
![18 \div 100 \times 68.75 =](https://tex.z-dn.net/?f=18%20%5Cdiv%20100%20%20%5Ctimes%2068.75%20%3D%20)
![= 12.38](https://tex.z-dn.net/?f=%20%3D%2012.38)