The concentration in mol/l of reactant after 1.5 s is calculated as follows
from first order integrated equation
In (A)t = - Kt + In (A)o where
At = final concentration =?
A)o =initial concentration =0.27 M
K = constant=0.75
T=temperature = 1.5 s
in( A)t = -0.75(1.5) + in(0.27)
In (A)t =-1.125 +-1.31 =-2.435
In(A)t =-2.435
In (A)t = e
find the e value
( A)t is therefore =0.0876 mol/l
"EMPIRICAL FORMULA" tells that!!
11 L because you just need to use a pie chart
Answer:
Explanation:
sp² hybridization is found in those compounds having double bond .
Out of the given compounds only C₂H₂Cl₂ has double bond so this compound contains carbon with sp² hybridization .
Rest have sp³ hybridization because they are saturated compounds .
