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Lesechka [4]
2 years ago
8

Automobile catalytic Converters use a platinum callus to reduce air pollution by changing emissions such as carbon monoxide CO2

to carbon dioxide CO2 the uncatalyzed reaction is represented by the balance inflation below 2 CO + 02 2CO2 + heat determine the number of moles of O2 reaction with 28 moles of CO during this reaction

Chemistry
1 answer:
natka813 [3]2 years ago
6 0

Answer:

14 mol O₂

Explanation:

The reaction between CO and O₂ is the following:

CO + O₂ → CO₂

We balance the equation with a coefficient 2 in CO and CO₂ to obtain the same number of O atoms:

2CO + O₂ → 2CO₂

As we can see from the balanced equation, 1 mol of O₂ is required to react with 2 moles of CO. Thus, the conversion factor is 1 mol of O₂/2 mol CO. We multiply the moles of CO by the conversion factor to calculate the moles of O₂ that are required:

28 mol CO x 1 mol of O₂/2 mol CO = 14 mol O₂

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If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w
Nata [24]

4.1g

Explanation:

Given parameters:

Mass of carbon dioxide = 15g

Mass of oxygen gas = 11g

Unknown:

Mass of carbon consumed = ?

Solution:

   Equation of the reaction:

                                              C +  O₂   →   CO₂

    To solve this problem from the balanced equation,  we have to use the amount of product formed and work to Carbon. This is because, we are sure of the amount of carbon dioxide formed but the amount of the given oxygen gas used is not precise.

  Number of moles of CO₂ = \frac{mass}{molar mass}

Molar mass of CO₂ = 12 + (16 x2) = 44g/mol

   Number of moles of CO₂ = \frac{15}{44} = 0.34mole

From the equation of the reaction;

              1 mole of CO₂  is produced from 1 mole of C

           0.34mole of CO₂  will produce 0.34mole of C

Mass of carbon reacting = number of moles x molar mass = 0.34 x 12 = 4.1g

Learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

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When 25.0 g of ch4 reacts completely with excess chlorine yielding 45.0 g of ch3cl, what is the percentage yield, according to c
Ber [7]

Taking into account definition of percent yield, the percent yield for the reaction is 57.08%.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CH₄ + Cl₂ → CH₃Cl + HCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CH₄: 1 mole
  • Cl₂: 1 mole
  • CH₃Cl: 1  mole
  • HCl:  1 mole

The molar mass of the compounds is:

  • CH₄: 16 g/mole
  • Cl₂: 70.9 g/mole
  • CH₃Cl: 50.45 g/mole
  • HCl:  36.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • CH₄: 1 mole ×16 g/mole= 16 grams
  • Cl₂: 1 mole ×70.9 g/mole= 70.9 grams
  • CH₃Cl: 1 mole ×50.45 g/mole= 50.45 grams
  • HCl: 1 mole ×36.45 g/mole= 36.45 grams

Mass of CH₃Cl formed

The following rule of three can be applied: if by reaction stoichiometry 16 grams of CH₄ form 50.45 grams of CH₃Cl, 25 grams of CH₄ form how much mass of CH₃Cl?

mass of CH_{3} Cl=\frac{25 grams of CH_{4}x 50.45grams of CH₃Cl }{16 grams of CH_{4}}

<u><em>mass of CH₃Cl= 78.83 grams</em></u>

Then, 78.83 grams of CH₃Cl can be produced from 25 grams of CH₄.

<h3>Percent yield</h3>

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield=\frac{actual yield}{theorical yield}x100

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Percent yield for the reaction in this case

In this case, you know:

  • actual yield= 45 grams
  • theorical yield= 78.83 grams

Replacing in the definition of percent yields:

percent yield=\frac{45 grams}{78.83 grams}x100

Solving:

<u><em>percent yield= 57.08%</em></u>

Finally, the percent yield for the reaction is 57.08%.

Learn more about

the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

percent yield:

brainly.com/question/14408642

#SPJ1

5 0
2 years ago
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