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Lesechka [4]
2 years ago
8

Automobile catalytic Converters use a platinum callus to reduce air pollution by changing emissions such as carbon monoxide CO2

to carbon dioxide CO2 the uncatalyzed reaction is represented by the balance inflation below 2 CO + 02 2CO2 + heat determine the number of moles of O2 reaction with 28 moles of CO during this reaction

Chemistry
1 answer:
natka813 [3]2 years ago
6 0

Answer:

14 mol O₂

Explanation:

The reaction between CO and O₂ is the following:

CO + O₂ → CO₂

We balance the equation with a coefficient 2 in CO and CO₂ to obtain the same number of O atoms:

2CO + O₂ → 2CO₂

As we can see from the balanced equation, 1 mol of O₂ is required to react with 2 moles of CO. Thus, the conversion factor is 1 mol of O₂/2 mol CO. We multiply the moles of CO by the conversion factor to calculate the moles of O₂ that are required:

28 mol CO x 1 mol of O₂/2 mol CO = 14 mol O₂

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In an acid-base titration experiment, 50 mL of a 0.05 M solution of acetic acid (Ka= 1.75 x 10-5 ) was titrated with a 0.05M sol
Viktor [21]

Answer:

(3) 5.36

Explanation:

Since this is a titration of a weak acid before reaching equivalence point, we will have effectively a buffer solution. Then we can use the Henderson-Hasselbalch equation to answer this question.

The reaction is:

HAc + NaOH ⇒ NaAc + H₂O

V NaOH = 40 mL x 1 L/1000 mL = 0.040 L

mol NaOH reacted with HAc = 0.040 L x 0.05 mol/L = 0.002 mol

mol HAC originally present = 0.050 L x 0.05 mol/L = 0.0025 mol

mol HAc left after reaction = 0.0025 - 0.002 = 0.0005

Now that we have calculated the quantities of the weak acid and its conjugate base in the buffer, we just plug the values into the equation

pH = pKa + log ((Ac⁻)/(HAc))

(Notice we do not have to calculate the molarities of  Ac⁻ and HAc because the volumes cancel in the quotient)

pH = -log (1.75 x 10⁻⁵) + log (0.002/0.0005) = 5.36

THe answer is 5.36

5 0
3 years ago
Read 2 more answers
HI PLEASE HELP!!!!
Crazy boy [7]

Answer:

I believe it's A generally increases may be wrong

8 0
3 years ago
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If δh = -70.0 kj and δs = -0.400 kj/k , the reaction is spontaneous below a certain temperature. calculate that temperature.
Trava [24]
According to this formula, when:

ΔG = ΔH  - T*ΔS

when the reaction is thermodynamically spontaneous ΔG < 0 

∴ ΔH - T* ΔS = 0 

∴T*ΔS = ΔH

∴ T = ΔH / ΔS

when we have:

ΔH = -70KJ

and ΔS = -0.4 KJ/K

So by substitution:

T =  -70KJ /- 0.4

  =  175 K 

∴the certain temperature below which the reaction will be thermodynamically spontaneous is 175 K  
4 0
4 years ago
13 <br> Help lol please thanks
slamgirl [31]

Answer:

Mass = 15.13 g

Explanation:

Given data:

Number of atoms of hydrogen = 8.11×10²³

Mass of ammonia formed = ?

Solution:

Chemical equation:

3H₂ + N₂          →    2NH₃

Number of moles of hydrogen:

1 mole contain 6.022× 10²³ atoms

8.11×10²³ atoms × 1 mol / 6.022× 10²³ atoms

1.35 mol

Now we will compare the moles of hydrogen and ammonia:

            H₂        :         NH₃

             3         :           2

           1.35      :         2/3×1.35 = 0.89 mol

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 0.89 mol × 17 g/mol

Mass = 15.13 g

5 0
3 years ago
GIVING BRAINIEST FIVE STARS AND HEART!
Romashka [77]

Answer:

Matter cannot be created destroyed

Explanation

Matter can change form through physical and chemical changes, but through any of these changes, matter is conserved. The same amount of matter exists before and after the change—none is created or destroyed. This concept is called the Law of Conservation of Mass.

4 0
3 years ago
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