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Lesechka [4]
2 years ago
8

Automobile catalytic Converters use a platinum callus to reduce air pollution by changing emissions such as carbon monoxide CO2

to carbon dioxide CO2 the uncatalyzed reaction is represented by the balance inflation below 2 CO + 02 2CO2 + heat determine the number of moles of O2 reaction with 28 moles of CO during this reaction

Chemistry
1 answer:
natka813 [3]2 years ago
6 0

Answer:

14 mol O₂

Explanation:

The reaction between CO and O₂ is the following:

CO + O₂ → CO₂

We balance the equation with a coefficient 2 in CO and CO₂ to obtain the same number of O atoms:

2CO + O₂ → 2CO₂

As we can see from the balanced equation, 1 mol of O₂ is required to react with 2 moles of CO. Thus, the conversion factor is 1 mol of O₂/2 mol CO. We multiply the moles of CO by the conversion factor to calculate the moles of O₂ that are required:

28 mol CO x 1 mol of O₂/2 mol CO = 14 mol O₂

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Use Hess's law. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2Ca(s) + O2(g) → 2CaO(s) ΔH = -1269.8 kJ We need to get rid of the Ca and O2 in the equations, so we need to change the equations so that they're on both sides so they "cancel" out, similar to a system of equations. I changed the second equation. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ The sign changes in the second equation above since the reaction changed direction. Next, we need to multiply the first equation by two in order to get the coefficients of the Ca and O2 to match those in the second equation. We also multiply the enthalpy of the first equation by 2. 2Ca(s) + 2CO2(g) + O2(g) → 2CaCO3(s) ΔH = -1625.6 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ Now we add the two equations. The O2 and 2Ca "cancel" since they're on opposite sides of the arrow. Think of it more mathematically. We add the two enthalpies and get 2CaO(s) + 2CO2(g) → 2CaCO3(s) and ΔH = -355.8 kJ. Finally divide by two to get the given equation: CaO(s) + CO2(g) → CaCO3(s) and ΔH = -177.9 kJ.

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2 years ago
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