Question

For the point P(2,-14) and Q(9,-9) find the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ

Answer 1

Answer:

Step-by-step explanation:

Distance : $\sqrt{(x2-x1)^2 + (y2 - y1)^2} = \sqrt{(9-2)^2 + (-9+14)^2}= \sqrt{49 + 25} = \sqrt{74}$

Midpoint :

x (m) = (2+9)/2 = 11/2

y (m) = (-14-9)/2 = -23/2

M (11/2, -23/2)