(3 4/7 - 3/5) x 2/3 = 208/105
3/2 x (3 4/7 - 3/5) = 156/35
That is what your two problems are when simplified.
From there on you can tell what is greater then another.
In this quadratic equation a=9 b=0 c=64, you could use the Quadratic Formula:
x = [-b +-sqrt (b^2 -4*a*c)] / 2*a
x = 0 +- sqrt (0 -4*9*64) / 2*9
x = +- sqrt(-2,304) / 18
x = + 48 i / 18
x = -48 i /18
Where "i" is the square root of minus 1.
Answer:
- 2 and 12
Step-by-step explanation:
let the 2 integers be x and y , x > y , then
x - y = 14 → (1)
x + y = 10 → (2)
add the 2 equations term by term to eliminate y
2x = 24 ( divide both sides by 2 )
x = 12
Substitute x = 12 into (2)
12 + y = 10 ( subtract 12 from both sides )
y = - 2
As a check
x + y = 12 + (- 2) = 12 - 2 = 10
x - y = 12 - (- 2) = 12 + 2 = 14
xy = 12 × - 2 = - 24
They will go over point 3,0 and /4,9 then
Answer:
The zeros are (-5,0) and (4,0)
Step-by-step explanation:
