Look at the picture.
![m\angle a=\dfrac{180^o-46^o}{2}=67^o\\\\m\angle b=180^o-67^o=113^o\\\\m\angle x=\dfrac{180^o-113^o}{2}=33.5^o\\\\Answer:\ [1]\ 33.5^o](https://tex.z-dn.net/?f=m%5Cangle%20a%3D%5Cdfrac%7B180%5Eo-46%5Eo%7D%7B2%7D%3D67%5Eo%5C%5C%5C%5Cm%5Cangle%20b%3D180%5Eo-67%5Eo%3D113%5Eo%5C%5C%5C%5Cm%5Cangle%20x%3D%5Cdfrac%7B180%5Eo-113%5Eo%7D%7B2%7D%3D33.5%5Eo%5C%5C%5C%5CAnswer%3A%5C%20%5B1%5D%5C%2033.5%5Eo)
I need help with the following question above please
1 answer:
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Answer:56.8 inches
Step-by-step explanation:
For perimeter we must find the lengths of the 2 diagonal sides of the triangle which are the same because it is isosceles.
the triangle is cut directly in half so both halves of the base are 17/2
17/2 = 8.5
solve through pythagoren theorum
altitude^2 + (half of base)^2 = (diagonal length)^2
18^2 + (8.5)^2 = (diagonal length)^2
324 + 72.25 = (diagonal length)^2
396.3 = (diagonal length)^2
= diagonal length
diagonal length = 19.9
diagonal length + diagonal length + base = perimeter
19.9 + 19.9 + 17 = perimeter
56.8 inches = perimeter