Answer:
Wyzant
Question
Flying against the wind, an airplane travels 4200 km in 7 hours. Flying with the wind, the same plane travels 4000 km in 4 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer · 1 vote
Let Va = the velocity of the airplane Let Vw = the velocity of the wind When flying with the wind: (Va+Vw)*(4 hours) = 4000 4Va + 4Vw = 4000 4Vw = 4000 - 4Va Vw = 1000 - Va When flying against the wind: (Va-Vw)*(7 hours) = 4200 km7Va - 7Vw = 4200 Substitute 1000-Va for Vw and solve for Va: 7Va - 7(1000-Va) = 4200 7Va -7000 + 7Va = 4200 14Va = 11200 Va = 800 km/hr Rate of wind: Vw = 1000 - Va = 1000 - 800 = 200 km/hour
More
Socratic
Question
Flying against the wind, an airplane travels 4500 in 5 hours. Flying with the wind, the same plane travels 4640 in 4 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer · 0 votes
The speed of plane in still air is 1030 km/hr and wind
Step-by-step explanation:
Answer:
8) 10°
9) X can not be determined.
10) 10°
11) 12 units.
Step-by-step explanation:
8) The three sides of the given triangle are equal. Hence, the triangle is an equilateral triangle, hence each angle will be 60°.
So, 6x = 60°
⇒ x = 10°.
9) The three angles of the given triangle are equal. Hence, the triangle is an equilateral triangle, hence each side will be equal.
So, 6x - 5 = 6x
So, x can not be determined from this equation.
10) Δ KLM is equilateral, so, KN will bisect ∠ MKL. So, ∠ NKL = 30°
Hence, 3x = 30°
⇒ x = 10°
11) In Δ XYZ, XZ = XY , so, ∠ Z = ∠ Y.
Again, ∠ X is given to be 60°.
Therefore, each angle is 60°.
So, the triangle XYZ is equilateral, and each side will be equal.
So, 3x + 8 = 4x - 4
⇒ x = 12 units. (Answer)
Answer: 3 x 13 ?
Step-by-step explanation:
The answer is 8.6 units.
To solve this problem you use the distance formula.
Hello, Welcome to Brainly I am papaguy expert User I will you if you have any questions so far you have on.
Answer: 3/5
