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____ [38]
3 years ago
8

find the root(s) of f (x) = (x + 5)3(x - 9)2(x + 1). 50 POINTS!!!!!!! -5 with multiplicity 3 5 with multiplicity 3 -9 with multi

plicity 2 9 with multiplicity 2 -1 with multiplicity 0 -1 with multiplicity 1 1 with multiplicity 0 1 with multiplicity 1
Mathematics
2 answers:
Dmitrij [34]3 years ago
8 0

Answer:

The answer to this question can be described as follows:

-5 with multiplicity 3

9 with multiplicity 2

-1 with multiplicity 1

Step-by-step explanation:

Given:

\Rightarrow f (x) = (x + 5)^3(x - 9)^2(x + 1)

Solve the above equation:

\Rightarrow f (x) = (x + 5)(x + 5)(x + 5)(x - 9)(x - 9)(x + 1)\\

The roots of the polynomial are as follows:

 \Rightarrow (x-x_1)(x-x_2)(x-x_3)......(x-x_n)\\\\\Rightarrow  x_1,x_2,x_3.........x_n

That's why the roots are:

5 with multiplicity 3

9 with multiplicity 2

-1 with multiplicity 1

AysviL [449]3 years ago
5 0

Answer:

answer:

a. -5 with multiplicity 3  

d. 9 with multiplicity 2

f. -1 with multiplicity 1

Step-by-step explanation:

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2 years ago
(6-7i)+(5+4i)= (simplified)
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Answer:

11-3i

Step-by-step explanation:

6-7i+5+4i=6+5-7i+4i=11-3i

8 0
3 years ago
Read 2 more answers
Click on the solution set below until the correct one is displayed​
Effectus [21]
What solution set below
7 0
3 years ago
Need help please !!!
irina1246 [14]

sin^2 x + 4 sinx +3       3 + sinx

--------------------------  =  -------------------

cos^2 x                        1 - sinx


factor the numerator


(sinx +3) (sinx+1)       3 + sinx

--------------------------  =  -------------------

cos^2 x                        1 - sinx


cos^2 = 1-sin^2x

(sinx +3) (sinx+1)       3 + sinx

--------------------------  =  -------------------

1- sin^2x                       1 - sinx

factor the denominator

(sinx +3) (sinx+1)       3 + sinx

--------------------------  =  -------------------

(1-sinx ) (1+sinx)                   1 - sinx

cancel the common term (1+sinx)  and (sinx +1)

(sinx +3)                       3 + sinx

--------------------------  =  -------------------

(1-sinx )                           1 - sinx


reorder the first term

3+sinx                           3 + sinx

--------------------------  =  -------------------

(1-sinx )                           1 - sinx

3 0
3 years ago
7900 dollars is placed in an account with an annual interest rate of 5.5%. How much will be in the account after 11 years?
My name is Ann [436]

Answer:

\$12,679.50

Step-by-step explanation:

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=11\ years\\ P=\$7,900\\ A=?\\r=5.5\%=5.5/100=0.055

substitute in the formula above

A=7,900(1+0.055*11)

A=7,900(1.605)

A=\$12,679.50

6 0
3 years ago
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