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Likurg_2 [28]
2 years ago
11

(0, 2), (1,7) create a equation that passes through each pair of points

Mathematics
1 answer:
uranmaximum [27]2 years ago
8 0

Answer:

y = 5x + 2

Step-by-step explanation:

Given the equation 5x + 2

Plug in 0

y = 5(0) + 2

y = 2

(0,2)

Given the equation 5x + 2

Plug in 1

y = 5(1) + 2

y = 7

(1,7)

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Find the slope of this line: (15,7) (3,-2)<br><br> Help
Oliga [24]

Answer:

m=\frac{3}{4}

Step-by-step explanation:

\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(15,\:7\right),\:\left(x_2,\:y_2\right)=\left(3,\:-2\right)

m=\frac{-2-7}{3-15}

\mathrm{Refine}

m=\frac{3}{4}

5 0
3 years ago
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katrin2010 [14]

Answer:

Sorry no idea

Step-by-step explanation:

I'm so sorry

3 0
3 years ago
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4 is the greasy common factor
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3 years ago
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Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear
AlladinOne [14]

Answer:

x=\frac{83}{50}

Step-by-step explanation:

we know that

If the three points are collinear

then

m_A_B=m_A_C

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope AB

we have

A(1,\frac{2}{3}),B(x,-\frac{4}{5})

substitute in the formula

m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}

m_A_B=\frac{\frac{-12-10}{15}}{x-1}

m_A_B=-\frac{22}{15(x-1)}

step 2

Find the slope AC

we have

A(1,\frac{2}{3}),C(-\frac{1}{2},4)

substitute in the formula

m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}

m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}

m_A_C=-\frac{20}{9}

step 3

Equate the slopes

m_A_B=m_A_C

-\frac{22}{15(x-1)}=-\frac{20}{9}

solve for x

15(x-1)20=22(9)

300x-300=198

300x=198+300

300x=498

x=\frac{498}{300}

simplify

x=\frac{83}{50}

8 0
3 years ago
1. Find the midpoint of the segment with endpoints of 6 3i and −12 − 5i. I.
Tju [1.3M]

Answer: what’s is the 5i

Step-by-step explanation:

8 0
2 years ago
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