Question

A man is sitting on a chair with wheels. He grabs a 2.1 kg book from the desk and throws

Answer 1

The speed of the man and the chair after the book is thrown is 0.2 m/s.

The given parameters:

• mass of the book, m₁ = 2.1 kg
• speed of the book, u₁ = 7.2 m/s
• mass of the man, M = 70 kg
• mass of the book, m = 9.2 kg

The total mass of the man and the book is calculated as follows;

m₂ = 70 kg + 9.2 kg

m₂ = 79.2 kg

The speed of the man and the chair after the book is thrown is determined by applying the principle of conservation of linear momentum;

$m_1 u_1 = m_2u_2\\\\u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{2.1 \times 7.2}{79.2} \\\\u_2 = 0.2 \ m/s$

Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/7538238