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Alex_Xolod [135]
3 years ago
12

What happens to the density of a substance as its temperature increases?

Physics
1 answer:
Dimas [21]3 years ago
7 0
The molecules spread apart, so they take up more space. Because of this, they are less dense.

This means the density decreases as temperature increases.
You might be interested in
A ball starts at rest and rolls down an inclined plane. The ball reaches 7.5 m/s in 3 seconds. What is the acceleration?
just olya [345]

Answer:

a=2.5\ m/s^2

Explanation:

<u>Motion With Constant Acceleration </u>

It's a type of motion in which the velocity of an object changes uniformly over time.

The equation that describes the change of velocities is:

v_f=v_o+at

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

Solving the equation for a:

\displaystyle a=\frac{v_f-v_o}{t}

The ball starts at rest (vo=0) and rolls down an inclined plane that makes it reach a speed of vf=7.5 m/s in t=3 seconds.

The acceleration is:

\displaystyle a=\frac{7.5-0}{3}

\boxed{a=2.5\ m/s^2}

7 0
2 years ago
What is the charge of the negative sphere
tatyana61 [14]

Answer:

electrons

Explanation:

8 0
2 years ago
What is kelvin scale?
Darina [25.2K]
<span>a scale of temperature with absolute zero as zero, and the triple point of water as exactly 273.16 degrees.</span>
4 0
3 years ago
Read 2 more answers
While playing a scavenger hunt game, Anthony walks 48.0 m to the south and then walks 12.0 m to the west. What single straight-l
Alenkasestr [34]
As these are distances created by moving in a straight line, using a trigonometric analysis can solve the missing single straight-line displacement. Looking at the 48m and 12m movements as legs of a triangle, obtaining the hypotenuse using the pythagorean theorem will yield us the correct answer.
This is shown below:

c^2 = 48^2 + 12^2
c = sqrt(2304 + 144)
c = sqrt(2448)
c = 49.48 m

To obtain the angle at which Anthony walks 49.48, we obtain the arc tangent of (12/48). This is shown below:

arc tan (12/48) =14.04 degrees.

Therefore, Anthony could have walked 49.48 m towards the S 14.04 W direction.
4 0
2 years ago
An object is launched with an initial velocity of 50.0 m/s at a launch angle of 36.9∘ above the horizontal. part a determine x-v
ankoles [38]
Given:
v = 50.0 m/s, the launch velocity
θ = 36.9°, the launch angle above the horizontal

Assume g = 9.8 m/s² and ignore air resistance.
The vertical component of the launch velocity is
Vy = (50 m/s)*sin(50°) = 30.02 m/s

The time, t, to reach maximum height is given by
(30.02 m/s) - (9.8 m/s²)*(t s) = 0
t = 3.0634 s
The time fo flight is 2*t = 6.1268 s

The horizontal velocity is
u = (50 m/s)cos(36.9°) = 39.9842 m/s
The horizontal distance traveled at time t is given in the table below.

Answer:

  t, s    x, m
------  --------
     0   0
     1   39.98
     2   79.79
     3   112.68
     4   159.58
     5   199.47
     6   239.37

5 0
3 years ago
Read 2 more answers
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