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oksian1 [2.3K]
4 years ago
5

What is capacitance?

Physics
1 answer:
Otrada [13]4 years ago
5 0

Answer:

A, the amount of charge stored per volt

Explanation:

The equation for capacitance is

C = Q/V

therefore, it is charge per volt

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raketka [301]

Answer:

B AND D

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3 years ago
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A 8.0-g bullet with an initial velocity of 115.0 m/s lodges in a block of wood and comes to rest at a
Gnesinka [82]
A. When your fire a bullet into the air, it typically takes between 20 and 90 second for it to come down,depending on the angle it was fired at,its muzzle velocity and caliber.
3 0
3 years ago
2. A uniform wire of resistance R is stretched until its length doubles. Assuming its density and resistivity remain constant, w
never [62]

Answer:

Resistance is quadrupled.

Explanation:

Solving this requires us to use the formula of resistivity.

Resistivity is usually said to be the measure of the resistance of a particular size of any given material to the electrical conduction. It is mathematically represented as

ρ = RA/L, where

ρ = the resistivity of the given material

R = the resistance of the material

A = the area of the material

L = length of the material.

From the question, we're told that the length is doubled with the resistivity and density remaining constant. If the density is constant, this makes the volume constant as well.

Volume, V = A * L. We're then told that the length is doubled. If the length is doubled, for the volume to remain constant, then the area must be halved.

Volume, V = A/2 * 2L

Making, Resistance R, subject of the formula, we have

R = ρL/A.

Since resistivity is constant and the area is halved, we then have

R = 2L / (1/2A)

R = 4L / A

If the length is doubled, we have the resistance to be quadrupled

3 0
3 years ago
Two stretched copper wires both experience the same stress. The first wire has a radius of 3.9×10-3 m and is subject to a stretc
maw [93]

The stretching force acting on the second wire, given the data is 588 N

<h3>Data obtained from the question</h3>
  • Radius of fist wire (r₁) = 3.9×10⁻³ m
  • Force of first wire (F₁) = 450 N
  • Radius of second wire (r₂) = 5.1×10⁻³ m
  • Force of second wire (F₂) =?

<h3>How to determine the force of the second wire</h3>

F₁ / r₁ = F₂ / r₂

450 / 3.9×10⁻³ = F₂ / 5.1×10⁻³

cross multiply

3.9×10⁻³ × F₂ = 450 × 5.1×10⁻³

Divide both side by 3.9×10⁻³

F₂ = (450 × 5.1×10⁻³) / 3.9×10⁻³

F₂ = 588 N

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

7 0
2 years ago
In the process of electricity, what flows through the wires?
MAVERICK [17]
I think the answer would be
C.Electrons
Hope this helps

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3 years ago
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