This is not a question kid
How many moles of oxygen atoms are present in 5
moles of Mg3(PO4)2
All you have to do is to create
a ratio between the molecule and the oxygen atom.
5 moles of Mg3(PO4)2 (4x2 moles
O/1 mole Mg3(PO4)2) = 40 moles of oxygen
The reaction is;
2Na + 2H2O → 2NaOH + H2
Answer:
4.4 × 10^(23) atoms
Explanation:
The reaction is;
2Na + 2H2O → 2NaOH + H2
2 moles of Na produces 1 mole of H2 from the equation reaction.
Thus, since 8.2 L of hydrogen gas at STP are produced. And we know that at STP, 1 mole of a gas will have a volume of 22.4 L, and also, We know according to avogadro's number that, 1 mol = 6.02 × 10^(23) atoms, Thus;
8.2 L of H2 × (1 mole of H2/22.4 L) × (2 mole of Na/1 mole of H2) × (6.02 × 10^(23) atoms/1 mole of Na) = 4.4 × 10^(23) atoms
Answer:
Following are the responses to the given question:
Explanation:
Please find the attached file for the solution.
