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EleoNora [17]
4 years ago
8

How many moles of oxygen atoms are present in 5 moles of Mg3(PO4)2

Chemistry
1 answer:
Irina18 [472]4 years ago
5 0

How many moles of oxygen atoms are present in 5 moles of Mg3(PO4)2

All you have to do is to create a ratio between the molecule and the oxygen atom.

5 moles of Mg3(PO4)2 (4x2 moles O/1 mole Mg3(PO4)2) = 40 moles of oxygen

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A student checks the air in her bicycle tires early in the morning when it is cool outside. If she measures it again later in th
Dmitry_Shevchenko [17]

Answer:

She will observe that the pressure on the tire is higher.

Explanation:

By the ideal gas law, the pressure and the temperature are directly proportional, so, if the temperature increases the pressure increases too:

PV = nRT (P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature).

The temperature is a measure of the average kinetic energy of the gas molecules, so when the temperature increases, the energy also increases, and the gas molecules will move more quickly, so they will collide more often between themselves and in the wall. Those collisions will be with more force because the velocity is higher.

So, the pressure will be higher, because it is the result of collisions of the gas molecules with the walls of the tire.

6 0
3 years ago
The population size of a predator species is directly controlled by _____. the population cycle of parasites the population cycl
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The population size of its prey 

6 0
3 years ago
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Marrrta [24]

Answeeeeer:

 A. cell

Explanation:

Since A is the smallest in the chart, that would correspond to the cell because thats the smallest out of Tissue, Organ and Organism.

3 0
3 years ago
Use the standard reduction potentials located in the 'Tables' linked above to calculate the equilibrium constant for the reactio
Paladinen [302]

Answer:

Check the explanation

Explanation:

cell CuE Ecell 0.337 (-0.14) Ecl0.477 V

Since E^o_{ cell } > 0 , the value of \Delta G^o will be negative.

\Delta G^o < 0

\Delta G^o =-nFE^o_{ cell }......(1)

But

\Delta G^o =-RT ln K......(2)

From (1) and (2)

\Delta G^o =-RT ln K=-nFE^o_{ cell }

ln K =\frac{nFE^o_{ cell } }{RT }

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6 0
3 years ago
Please help! :)
Reika [66]

Answer:

There will be 525.2 grams of K3N produced

Explanation:

Step 1: Data given

Number of moles of potassium oxide ( K2O) = 6 moles

Magnesium nitride (Mg3N) = in excess

Molar mass of K3N = 131.3 g/mol

Step 2: The balanced equation

Mg3N2 + 3K2O → 3MgO + 2K3N

Step 3: Calculate moles of K3N

The limiting reactant is K2O.

For 1 mol Mg3N2 consumed, we need 3 moles of K2O to produce 3 moles of MgO and 2 moles of K3N

For 6 moles K2O we'll have 2/3 * 6 = 4 moles of K3N

Step 4: Calculate mass of K3N

Mass of K3N = moles K3N * molar mass K3N

Mass of K3N = 4 moles * 131.3 g/mol

Mass of K3N = 525.2 grams

There will be 525.2 grams of K3N produced

8 0
3 years ago
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