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strojnjashka [21]
3 years ago
13

If 8.2 L of hydrogen gas at STP are produced in this reaction, how many atoms of sodium react?

Chemistry
1 answer:
kati45 [8]3 years ago
5 0

The reaction is;

2Na + 2H2O → 2NaOH + H2

Answer:

4.4 × 10^(23) atoms

Explanation:

The reaction is;

2Na + 2H2O → 2NaOH + H2

2 moles of Na produces 1 mole of H2 from the equation reaction.

Thus, since 8.2 L of hydrogen gas at STP are produced. And we know that at STP, 1 mole of a gas will have a volume of 22.4 L, and also, We know according to avogadro's number that, 1 mol = 6.02 × 10^(23) atoms, Thus;

8.2 L of H2 × (1 mole of H2/22.4 L) × (2 mole of Na/1 mole of H2) × (6.02 × 10^(23) atoms/1 mole of Na) = 4.4 × 10^(23) atoms

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When a redox reaction that takes place in an acidic solution involves an oxygen imbalance, oxygen should be balanced by adding _
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Oxygen should be balanced by adding H_{2}O  as needed, while hydrogen should be balanced by adding H^{+}.

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The Half-Equation Method is one technique used to balance redox processes. The equation is divided into two half-equations using this technique: one for oxidation and one for reduction.

By changing the coefficients and adding H_{2}O, H^{+}, and e^{-} in that order, each reaction is brought into equilibrium:

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The maximum amount of nickel(II) cyanide that will dissolve in a 0.220 M nickel(II) nitrate solution is...?
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Answer : The maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

Explanation :

The solubility equilibrium reaction will be:

                       Ni(CN)_2\rightleftharpoons Ni^{2+}+2CN^-

Initial conc.                        0.220       0

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