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strojnjashka [21]
3 years ago
13

If 8.2 L of hydrogen gas at STP are produced in this reaction, how many atoms of sodium react?

Chemistry
1 answer:
kati45 [8]3 years ago
5 0

The reaction is;

2Na + 2H2O → 2NaOH + H2

Answer:

4.4 × 10^(23) atoms

Explanation:

The reaction is;

2Na + 2H2O → 2NaOH + H2

2 moles of Na produces 1 mole of H2 from the equation reaction.

Thus, since 8.2 L of hydrogen gas at STP are produced. And we know that at STP, 1 mole of a gas will have a volume of 22.4 L, and also, We know according to avogadro's number that, 1 mol = 6.02 × 10^(23) atoms, Thus;

8.2 L of H2 × (1 mole of H2/22.4 L) × (2 mole of Na/1 mole of H2) × (6.02 × 10^(23) atoms/1 mole of Na) = 4.4 × 10^(23) atoms

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Answer:

90.37 g

Explanation:

From Avogadro Number,

1 mole of every substance contains a particle number of 6.02×10²³

From the question,

1 mole of CH₄ contains 6.02×10²³ molecules.

But,

1 mole of CH₄ has a mass of 16 g

Therefore,

16 g of CH₄ contains 6.02×10²³ molecules

Then,

Y g will contain 3.4×10²⁴ molecules

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Y = (16× 3.4×10²⁴)/(6.02×10²³)

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