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3 years ago

What is the value of x?

Mathematics

1 answer:

REY [17]3 years ago

5 0

Answer:

The missing side has a length equal to $15\sqrt{3}$

Step-by-step explanation:

We need to find the length of the missing side on the right triangle. We were given the length of the hypotenuse, and the opposite cathetus, therefore we can use the sine relation. This is done below:

$sin60=\frac{x}{30}\\\frac{\sqrt{3}}{2}=\frac{x}{30}\\x=15\sqrt{3}$

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Which expression is not equivalent to

zheka24 [161]

Answer:

B i think I'm kinda sure tho

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2 years ago

What are the factors of x^2-64

mel-nik [20]

Difference Of Two Squares
<span>a^2 - b^2 = a^2 - b^2
</span><span>so
x^2-64
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8 0

3 years ago

Each package of pens contains 3 pens. How is the number of pens related to the number of packages?

yuradex [85]

Answer: The correct option is (C) Packages x 3 = Pens

Step-by-step explanation: Given that each package of pens contains 3 pens.

We are to choose the correct mathematical relation between number of pens and number of packages.

Let, n represents the number of pens and N represents the number of packages.

Then, according to the given information, we have

$n\times 3=N\\\\\Rightarrow \textup{Packages}\times 3=\textup{Pens}.$

Thus, the correct relation is

Packages x 3 = Pens.

Option (C) is CORRECT.

6 0

3 years ago

Sam drew sticks and circles to solve this problem. Explain how he added. Then write the total.

TiliK225 [7]

He would have done 10+10+10 like for each stick then + How ever many ones there were and then we would have done the same for the other set . Soorry if I'm wrong

6 0

3 years ago

If s(x)=x-7 and t(x) =4x^2+3 which expression is equivalent to (t×s)(x)

marshall27 [118]

Answer:

$\large\boxed{(t\times s)(x)=4x^3-28x^2+3x-21}$

Step-by-step explanation:

$s(x)=x-7\\t(x)=4x^2+3\\\\(t\times s)(x)=t(x)\times s(x)\\\\\text{Substitute:}\\\\(t\times s)(x)=(4x^2+3)(x-7)\\\\\text{use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(t\times s)(x)=(4x^2)(x)+(4x^2)(-7)+(3)(x)+(3)(-7)\\\\=4x^3-28x^2+3x-21$

8 0

3 years ago