Question

What is the slope of a line parallel to the line containing (-6,1) and (3,-2)

Answer 1

Answer:

$m = -\frac{3}{9}$

Step-by-step explanation:

Use the following formula:

slope: $m = (y_{2} - y_{1})/(x_{2} - x_{1})$

Let:

$(x_{1} , y_{1}) = (-6 , 1)\\ (x_{2} , y_ {2}) = (3 , -2)$

Plug in the corresponding numbers to the corresponding variables:

$m = \frac{-2 - 1}{3 - (-6)}\\\\m = \frac{-3}{3 + 6}\\\\m = \frac{-3}{9}$

$m = -\frac{3}{9}$ is your answer.

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