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3 years ago

- HAM & CHEESE How much more doesthe ham and cheese omelet cost than thecheese omelet?

Mathematics

1 answer:

Bogdan [553]3 years ago

4 0

Answer:

$1.40 more

Step-by-step explanation:

Let's say:

A costs $z

and

B costs $y

A is more expensive than B. That means z is greater than y. When we will be asked to find HOW MUCH MORE A costs than B, we will have to subtract the smaller dollar value (which is y) FROM the larger dollar value (which is z).

So, we would say A costs more than B by ($z - $y).

Similarly, in this problem, see attached image, the HAM AND CHEESE costs MORE ($4.95) than the CHEESE ONLY ($3.55). How much more??

To find this, we subtract smaller value (3.55) from the larger value (4.95). Thus we have:

$4.95-3.55=1.40$

Ham and cheese omelet costs $1.40 more than cheese omelet.

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<h2>1. The "required option c) 45" is correct.</h2><h2>2. The value of 8 − 2⋅3 + 7 = 9</h2><h2>3. The required "option c) 45" is correct.</h2><h2>4. The required "option a) 40" is correct.</h2><h2>5. The value of $3^2-2.3+5$ = 8</h2>

Step-by-step explanation:

1. We have,

$5^2$ + 20

To find, the value of $5^2$ + 20 = ?

∴ $5^2$ + 20

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= 25 + 20

= 45

Thus, the "required option c) 45" is correct.

2. We have,

8 − 2⋅3 + 7

To find, the value of 8 − 2⋅3 + 7 = ?

∴ 8 − 2⋅3 + 7

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= 15 - 6

= 9

Thus, the value of 8 − 2⋅3 + 7 = 9

3. We have,

$6^2+3^2$

To find, the value of $6^2+3^2$ = ?

∴ $6^2+3^2$

= 6 × 6 + 3 × 3

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Thus, the required "option c) 45" is correct.

4. We have,

$2^{3} +4.8$

To find, the value of $2^{3} +4.8$ = ?

∴ $2^{3} +4.8$

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= 8 + 32

= 40

Thus, the value of $2^{3} +4.8$ = 40

Thus, the required "option a) 40" is correct.

5 . We have,

$3^2-2.3+5$

To find, the value of $3^2-2.3+5$ = ?

∴ $3^2-2.3+5$

= 3 × 3 - 2 × 3 + 5

= 9 - 6 + 5

= 14 - 6

= 8

Thus, the value of $3^2-2.3+5$ = 8

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

For f + g, we are simply adding the 2 together

<em>Domain: All values of x work, as any value x outputs any value y</em>

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<em>Domain: All values of x work, as any value x outputs any value y</em>

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<em>Domain: All values of x work, as any value x outputs any value y</em>

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<em>Domain: All values except for 0 work (undefined error), so asymptote at x = 0</em>

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3 years ago

- HAM & CHEESE How much more doesthe ham and cheese omelet cost than thecheese omelet?​

- HAM & CHEESE How much more doesthe ham and cheese omelet cost than thecheese omelet?