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WITCHER [35]
3 years ago
14

- HAM & CHEESE How much more doesthe ham and cheese omelet cost than thecheese omelet?​

Mathematics
1 answer:
Bogdan [553]3 years ago
4 0

Answer:

$1.40 more

Step-by-step explanation:

Let's say:

A costs $z

and

B costs $y

A is more expensive than B. That means z is greater than y. When we will be asked to find HOW MUCH MORE A costs than B, we will have to subtract the smaller dollar value (which is y) FROM the larger dollar value (which is z).

So, we would say A costs more than B by ($z - $y).

Similarly, in this problem, see attached image, the HAM AND CHEESE costs MORE ($4.95) than the CHEESE ONLY ($3.55). How much more??

To find this, we subtract smaller value (3.55) from the larger value (4.95). Thus we have:

4.95-3.55=1.40

Ham and cheese omelet costs $1.40 more than cheese omelet.

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iVinArrow [24]

Answer:

  A, C, D

Step-by-step explanation:

One way to answer this question is to use synthetic division to find the remainder from division of the polynomial by (x-3). If the polynomial is written in Horner form, evaluating the polynomial for x=3 is substantially similar.

  A(x) = ((x -2)x -4)x +3

  A(3) = ((3 -2)3 -4)3 +3 = -3 +3 = 0 . . . . . has a factor of (x -3)

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  B(x) = ((x +3)x -2)x -6

  B(3) = ((3 +3)3 -2)3 -6 = (16)3 -6 = 42 . . . (x -3) is not a factor

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  C(x) = (x -2)x^3 -27

  C(3) = (3 -2)3^3 -27 = 0 . . . . . . . . . . . . . has a factor of (x -3)

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  D(x) = (x^3 -20)x -21

  D(3) = (3^3 -20)3 -21 = (7)3 -21 = 0 . . . . has a factor of (x -3)

___

The polynomials of choice are A(x), C(x), and D(x).

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<u><em>≡ We know that:</em></u>
⇔ (x_{1},y_{1}) → (-4,-5)
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<u><em>≡ Solution:</em></u>
⇒ \sqrt{[(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}]}
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