Question

LAST ATTEMPT IM MARKING AS BRAINLIEST!! (Finding missing sides- similar triangles Algebraic practice )

Answer 1

Answer:

x=7.85

Step-by-step explanation:

Give the triangles we know that:

$\frac{cd}{fh} = \frac{de}{hg} = \frac{ce}{gf}$

Now we can substitute like usual

$\frac{78}{fh} = \frac{117}{54} = \frac{ce}{5x + 1}$

Now we simplify the fraction in the middle

the middles fraction will =13/6

Therefore:

$\frac{78}{fh} = \frac{13}{6}$

so 13fh=468

Therefore: fh=36

Now we can use the Pythagorean theorem

so

$gf = \sqrt{ {54}^{2} - {36}^{2} }$

so gf=18√5

so 5x+1=18√5

so 5x=-1+18√5

so x=7.85

(I'm not too sure about this one tho)