Answer:
Step1:start
step2: enter the ten number
s3: if the number is divided by 2 then print even number
s4: otherwise print odd number
s5:stop
Answer:
use a wizard or use a design view
Explanation:
i took the test
nu it would not but if they call microsoft to check it then yez the history would show up for them but dont try to make it notice able so they dont have to call
Answer:
Assuming an upstander is someone that opposes cyberbullying:
(1) Call them out
(2) Report the behavior to proper moderation authority
(3) Tell the person to block messages from the cyberbully
I don't really know what else you want from this.
Cheers.
Answer:
showProduct(int,double)
for example: showProduct(10,10.5) is the correct answer even showProduct(10,10.0) is also correct but showProduct(10.0,10.5) or showProduct(10,10) or showProduct(10.0,10) are wrong calls.
Explanation:
The code is
- <em>public static void showProduct (int num1, double num2){</em>
- <em> int product;</em>
- <em> product = num1*(int)num2;</em>
- <em> System.out.println("The product is "+product);</em>
- <em> }</em>
showProduct is function which asks for two arguments whenever it is called, first one is integer and second one is of type double which is nothing but decimal point numbers. Generally, in programming languages, 10 is treated as integer but 10.0 is treated as decimal point number, but in real life they are same.
If showProduct( 10,10.0) is called the output will be 'The product is 100'.
Strange fact is that, if you enter showProduct(10,10.5) the output will remain same as 'The product is 100'. This happens because in the 3rd line of code,which is <em>product=num1*(int)num2</em>, (int) is placed before num2 which makes num2 as of type integer, which means whatever the value of num2 two is given, numbers after decimal is erased and only the integer part is used there.
This is necessary in JAVA and many other programming languages as you <u>cannot</u><u> multiply two different datatypes</u> (here one is int and another is double). Either both of them should be of type int or both should be of type double.