#accepting input from user
n=int(input("Enter a number: "))
#entered number is stored in a temporary variable
temp=n
#initializng required variables
rev=0
dgt=0
#digits are reversed inside while loop
while(n>0):
dgt=n%10
rev=rev*10+dgt
n=n//10
#original number and its reverse are compared
if(temp==rev):
#if equal, it's a palindrome
print("It is a Palindrome")
else:
#if not equal, it's not a palindrome
print("It is not a Palindrome")
#◌⑅⃝●♡⋆♡Nåmřāthā♡⋆♡●⑅◌
Answer:
public class Digits
{
public static boolean allDigitsOdd(int num)
{
boolean flag=true;
int rem;
while(num>0)
{
rem=num%10;
num=num/10;
if(rem%2==0) // if a even digit found immediately breaks out of loop
{
flag=false;
break;
}
}
return flag; //returns result
}
public static void main(String args[])
{
System.out.println(allDigitsOdd(1375)); //returns true as all are odd digits
}
}
OUTPUT :
true
Explanation:
Above program has 2 static methods inside a class Digits. Logic behind above function is that a number is divided by 10 until it is less than 0. Each time its remainder by 0 is checked if even immediately breaks out of the loop.
The closest line to that would be the first line:
#!/bin/bash
echo "Hello World!"
BTW, the "#!" is referred to as a she-bang. When those are the first characters executed, the (requires an absolute path) program that follows is launched, and the rest of this file is given to it as data. To run this like a program, the execute permissions need to be set ( chmod 0755 script.sh ).
The answer is A, or Locating bottlenecks in a network.
