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The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

2 years ago

Help pls need answer asap

Varvara68 [4.7K]

Answer:

Carl traveled 281.25 km by bus and 1,618.75 km by plane.

Step-by-step explanation: v1 = 60 km/h average speed by bus to Toronto

v2 = 700 km/h average speed by plane to Winnipeg

d = 1,900 km the total distance traveled

t = 7 h total traveling time

t1 = the time of the travel by bug

t2 = the time of the travel by plane

t = t1 + t2 the total time

d1 = the distance traveled by bus

d2 = the distance traveled by plane

d = d1 + d2 the total distance

Since average speed = distance/time we have time = distance/avg.speed

t1 = d1/v1 that is t1 = d1/60

t2 = d2/v2 that is t2 = d2/700

Plug the above values into t1 + t2 = t.

We have the following system of equations:

d1/60 + d2/700 = 7

d1 + d2 = 1900

.......

Click here to see the step by step solution for 'd1' and 'd2'

.......

d1 = 281.25 km

d2 = 1,618.75 km

Carl traveled 281.25 km by bus and 1,618.75 km by plane.

7 0

2 years ago

13/2 divided by 3/4

Juliette [100K]

Answer: 26/3

Step-by-step explanation: When dividing by a fraction, we can change

the division sign to multiplication and flip the second fraction.

So 13/2 ÷ 3/4 means the same thing as 13/2 · 4/3.

So when dividing by a fraction, we can just multiply

by the reciprocal of that fraction or that fraction flipped.

Next we cross-cancel.

4 and 2 reduce to 2 and 1.

Multiplying across the numerator and denominators we have 26/3.

5 0

3 years ago

Where the numerator is larger than the denominator

gregori [183]

A fraction with a numerator that is greater than or equal to the denominator is known as an improper fraction.

4 0

3 years ago

Read 2 more answers

Line segment YV of rectangle YVWX measures 24 units.

oksian1 [2.3K]

Answer: $YX=13.85\ units$

Step-by-step explanation:

<h3> The complete exercise is: "Line segment YV of rectangle YVWX measures 24 units. What is the length of line segment YX?"</h3><h3> The missing figure is attached.</h3>

Since the figure is a rectangle, you know that:

$WV=YX\\\\YV=XW=24$

Notice that the segment YV divides the rectangle into two equal Right triangles.

Knowing the above, you can use the following Trigonometric Identity:

$tan\alpha =\frac{opposite}{adjacent}$

You can identify that:

$\alpha =30\°\\\\opposite=YX\\\\adjacent=YV=24$

Therefore, in order to find the length of the segment YX, you must substitute values into $tan\alpha =\frac{opposite}{adjacent}$ and then you must solve for YX.

You get that this is:

$tan(30\°)=\frac{YX}{24}\\\\(24)(tan(30\°))=YX\\\\YX=13.85$

7 0

3 years ago

Read 2 more answers