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Zarrin [17]
2 years ago
13

X^4-x^3.Please help me solve this.​

Mathematics
1 answer:
Keith_Richards [23]2 years ago
7 0

Answer:

you cant subtract they arent the same

Step-by-step explanation:

you cant

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Please help me graph question
iogann1982 [59]

Answer:

Step-by-step explanation:

Put in the form of y = Ax + B

x + 2y = 10

2y = -x + 10

y = -½x + 5

has a slope of -½ and a y intercept of 5

-x + 4y = 8

4y = x + 8

y = ¼x + 2

has a slope of ¼ and a y intercept of 2

4 0
2 years ago
8-1 1/5<br> (Simplify your answer. Type a whole number, fraction, or a mixed number.)<br> orrect:
ozzi
The answer is 6 4/5!
6 0
3 years ago
Read 2 more answers
8-2x=5-4x<br> 4+3x=2-2x<br> 2(x-1)+2(3x-1)=0
vodka [1.7K]

Answer:

See the below part

Step-by-step explanation:

1)

8 - 2x = 5 - 4x

=> 8 - 5 = -4x + 2x

=> 3 = -2x

=> 3/-2 = x

=> -3/2 = x

2)

4 + 3x = 2 - 2x

=> 4 - 2 = -2x - 3x

=> -2 = -5x

=> 2 = 5x

=> 2/5 = x

3)

2(x - 1) + 2(3x - 1) = 0

=> 2x - 2 + 6x - 2 = 0

=> 8x - 4 = 0

=> 8x = 4

=> x = 4/8

=> x = 1/2

8 0
2 years ago
Read 2 more answers
16x-4=31+12x please help I'm so confused
kolezko [41]
By the way I looked this up but heres the best ive got
<span>Simplifying (-1x + 27) + (16x + 4) = 0 Reorder the terms: (27 + -1x) + (16x + 4) = 0 Remove parenthesis around (27 + -1x) 27 + -1x + (16x + 4) = 0 Reorder the terms: 27 + -1x + (4 + 16x) = 0 Remove parenthesis around (4 + 16x) 27 + -1x + 4 + 16x = 0 Reorder the terms: 27 + 4 + -1x + 16x = 0 Combine like terms: 27 + 4 = 31 31 + -1x + 16x = 0 Combine like terms: -1x + 16x = 15x 31 + 15x = 0 Solving 31 + 15x = 0 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-31' to each side of the equation. 31 + -31 + 15x = 0 + -31 Combine like terms: 31 + -31 = 0 0 + 15x = 0 + -31 15x = 0 + -31 Combine like terms: 0 + -31 = -31 15x = -31 Divide each side by '15'. x = -2.066666667 Simplifying x = -2.066666667</span>
4 0
3 years ago
Please help and leave explanation
chubhunter [2.5K]

Answer: x = 150°

Step-by-step explanation:

The tangent intersects the circle's radius at a 90° angle, so ∠OAC = ∠OBC = 90°.

AOBC is a quadrilateral and we know that sum of interior angles of quadrilateral equals to 360°.

Now,

∠OAC + ∠OBC + ∠AOB + ∠ACB = 360°

90° + 90° + x + 30° = 360°

210° + x = 360°

x = 360° - 210°

x = 150°

7 0
3 years ago
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