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antoniya [11.8K]
3 years ago
15

2 questions in the pictures, it's grade 9 algebra 1 giving brainliest for first answer 50 points

Mathematics
1 answer:
butalik [34]3 years ago
8 0

write the above equation in the form of y = g(x).

⇒ y = (0.5)x + 3 – 4

Now, we convert the equation into y = mx + c form.

⇒ y = (0.5)x - 1

Here, we see that m = slope = 0.5, and c = y-intercept = -1.


Hence, the graph of g(x) = (0.5)x + 3 – 4 is a straight line with slope = 1/2 and y-intercept = -1.

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Mayflower Communications is the cheaper plan

Step-by-step explanation:

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4 years ago
Seriously need help with this question or I will fail my senior year
nlexa [21]

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Step-by-step explanation:

Tring to cheat because you don't feel like doing it. Hopefully you fail so you can learn your lesson

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Simplify tan9x-tan5x / 1+tan9xtan5x<br> (SHOW WORK)
Charra [1.4K]

Answer:

The simplest form is tan(4x)

Step-by-step explanation:

* Lets revise the identity of the compound angles

- tan(a+b)=\frac{tan(a)+tan(b)}{1-tan(a)tan(b)}

- tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}

* Lets solve the problem

- Let 9x = 5x + 4x

∴ tan(9x) = tan(5x + 4x)

- Use the rule of the compound angle

∵ \frac{tan(9x)-tan(5x)}{1+tan(9x)tan(5x)} ⇒ (1)

∵ tan(5x+4x)=\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)} ⇒ (2)

∵ tan(9x) = equation (2)

- Substitute (2) in (1)

∴ \frac{\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)}-tan(5x)}{1+(\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)})tan(5x)}

- Multiply up and down by (1 - tan(5x)tan(4x))

∴ \frac{tan(5x)+tan(4x)-tan(5x)[1-tan(5x)tan(4x)]}{1-tan(5x)tan(4x)+tan(5x)[tan(5x)+tan(4x)]}

- Simplify up and down

∴ \frac{tan(5x)+tan(4x)-tan(5x)+tan^{2}(5x)tan(4x)}{1-tan(5x)tan(4x)+tan^{2}(5x)+tan(5x)tan(4x) }

∴ \frac{tan(4x)+tan^{2}(5x)tan(4x)}{[1+tan^{2}(5x)]}

- Take tan(4x) as a common factor up

∴ \frac{tan(4x)[1+tan^{2}(5x)]}{[1+tan^{2}(5x)]}

- Cancel [1 + tan²(5x)] up and down

∴ The answer is tan(4x)

4 0
4 years ago
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