The least weight of a bag in the top 5 percent of the distribution is; 246
From the complete question below, we are given;
Population mean; μ = 240
Population standard deviation; σ = 3
Z-score formula is;
z = (x' - μ)/σ
- Now, we want to find the least weight in the top 5 of the distribution and as such we will use;
1 - 0.05/2 = 0.025 as significance level
Z-score at significance level of 0.025 is 1.96
Thus;
1.96 = (x' - 240)/3
3 × 1.96 = x' - 240
x' = 240 + 5.88
x' = 245.88
Approximating to a whole number gives;
x' = 246
Complete question is;
A machine is used to fill bags with a popular brand of trail mix. The machine is calibrated so the distribution of the weights of the bags of trail mix is normal, with mean 240 grams and standard deviation 3 grams. Of the following, which is the least weight of a bag in the top 5 percent of the distribution?
Read more about z-score at; brainly.com/question/25638875
Answer:
What is the meeting on? What site?
Explanation:
Hello
We can approach science from various angles. It may be that our aim is to solve a problem or to try to understand something. But, at the same time, what we find in it as explanatory or credible may be different if our profession is to be a trader, an importer of industrial equipment, a researcher or a teacher. Our concerns about science may differ according to the angle from which we think about it. That is to say, what is important when judging or evaluating science is different according to our relationship with it at certain times: whether we see it as producers, disseminators or consumers. Therefore, from the outset we have an area of complexity in thinking about science from our starting point.
The final rotational speed ω_final and the instantaneous power P delivered to the wheel are; ω_f = √((ω_i)² + 2(FL/(kmr²) and P = Frω_i
<h3>What is the Instantaneous Power?</h3>
A) From rotational kinematics, the formula for the final angular velocity is;
ω_f = √((ω_i)² + 2αθ)
where;
α is angular acceleration
θ = L/r. Thus;
ω_f = √((ω_i)² + 2α(L/r))
Now, α = T/I
Where;
I is moment of inertia = k*m*r²
T is t o r q u e = F * r
Thus;
α = (F * r)/(kmr²)
α = F/(kmr)
ω_f = √((ω_i)² + 2(F/(kmr))(L/r))
ω_f = √((ω_i)² + 2(FL/(kmr²)
B) Formula for instantaneous power is;
P = Fv
where at t = 0; v = rω_i
Thus;
P = Frω_i
Read more about Instantaneous Power at; brainly.com/question/14244672