A 1.5 standard deviation above the mean is
np + 1.5 <span>√(np(1-p))
We are given with
np = 200
p = 200/n
The standard deviation is
</span><span>√200(1-200/n))
Substituting
200 + 1.5 </span>√200(1-200/n))
By inspection, if the value of n is 200, then the radical will result to the value of 1. Only by increasing the value of n greater than 200 will the radical result to a value of less than 1 and decreasing the spread of the mean.
The answer is
the minimum is 201
the maximum is infinity
Answer:
1045384620173418506891046 number of copies
Step-by-step explanation:
10464929103984753671930600 ×55215278300
Answer:
k=20
Step-by-step explanation:
when x approaches 4, the denominator x-4 approaches 0
if the denominator is 0, it means that this is invalid
if the function is a number over 0 when x=4, it represents a vertical asymptote, which means no limit
so the only way possible to let there be a limit is to let the function be 0/0 when we plug in x=4
so x^2 + x - k = 0 when x = 4
4^2 + 4 - k = 0 ==> 20 - k = 0 ==> k = 20
Perimeter formula
p = 2l + 2w
I reverse left-right side
2l + 2w = p
Move 2l to the right
2l + 2w = p
2w = p - 2l
Move 2 to the right
2w = p - 2l
w = (p - 2l)/2
Summary
p = 2l + 2w
2l + 2w = p
2w = p - 2l
w = (p-2l)/2
