Answer:
f'(x) = -1/(1 - Cos(x))
Step-by-step explanation:
The quotient rule for derivation is:
For f(x) = h(x)/k(x)

In this case, the function is:
f(x) = Sin(x)/(1 + Cos(x))
Then we have:
h(x) = Sin(x)
h'(x) = Cos(x)
And for the denominator:
k(x) = 1 - Cos(x)
k'(x) = -( -Sin(x)) = Sin(x)
Replacing these in the rule, we get:

Now we can simplify that:

And we know that:
cos^2(x) + sin^2(x) = 1
then:

Option C
The ratio for the volumes of two similar cylinders is 8 : 27
<h3><u>
Solution:</u></h3>
Let there are two cylinder of heights "h" and "H"
Also radius to be "r" and "R"

Where π = 3.14 , r is the radius and h is the height
Now the ratio of their heights and radii is 2:3 .i.e

<em><u>Ratio for the volumes of two cylinders</u></em>

Cancelling the common terms, we get

Substituting we get,



Hence, the ratio of volume of two cylinders is 8 : 27
Answer:
Triangle DEF is a right, scalene triangle. It is not isosceles, obtuse, acute, or equilateral
Step-by-step explanation:
All we know about m and n are that they are not equal to each other and they are positive. This was given in the problem. See image. Once it is graphed you can see on the graph the lengths of DE and EF. Use Pythagorean theorem to calculate DF. see image.
DE is horizontal and EF is vertical, so you can see their slopes or calculate using a formula. Calculate the slope of DF. Slope is y-y on top of a fraction and x-x on the bottom of the fraction.
Lastly, use midpoint formula to find the midpoints. Average the x's and average the y's to find the x- and y-coordinates of the midpoints. See image.
Finally, DEF is a right triangle. The graph as well as the slopes show us that DE and EF form a right angle. So DEF must be a right triangle (and not obtuse nor acute) We were told that m doesNOT equal n, so the triangle cannot have two equal sides, so it cannot be isosceles (2 equal sides) nor equilateral (3 equal sides) It has 3 different lengths of sides; that is called scalene.
The first relation is a function, the others no
Answer:
a. Mean
Step-by-step explanation:
We have been given that the Sally is interested in taking a job in a city in which she's not familiar with the cost of living. She is especially concerned about the cost of housing and is interested in the average cost of a three bedroom home.
We know that in a normal distribution all central tendencies (mean, mode, median) are equal.
When a very large or very small valued data point is added to data set, mean is mostly affected by that outlier.
We know that mode of a data set is the point that appears at-most in the data set, so outliers doesn't affect mode.
Median of a data set is less affected by outliers.
The price of the three bedroom homes owned by millionaires will be greater than prices of houses owned by people in the neighborhood.
Therefore, mean will be most influenced by three bedroom homes owned by millionaires.