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3 years ago

14

10 POINTS!!! Name an angle that is adjacent to ∠BOC.

1 answer:

bogdanovich [222]3 years ago

5 0

An angle adjacent to BOC would be COD or BAC.

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Please help me with this Question

lutik1710 [3]

I did a good time at work but I got to get it done I got my car back and I’m gonna was a great

4 0

2 years ago

5. How long is the diagona of a 12 ft-by-16 ft rectangular garden?

kupik [55]

Answer:

The correct answer is option D, 20ft

Step-by-step explanation:

After drawing the picture below, you can just use pythagorean theorem to solve for the diagonal, or the hypotenuse in this case;

(Length)² + (Width)² = (Diagonal)²

(16)² + (12)² = (Diagonal)²

256 + 144 = (Diagonal)²

400 = (Diagonal)²

$\sqrt{400}$ = $\sqrt{Diagonal^{2} }$

<em>20 = Diagonal</em>

<em>Hope this helps!</em>

7 0

2 years ago

Read 2 more answers

What is another way to name 1\4?

Dafna1 [17]

You can write 1/4 as a decimal, equivalent fraction, and a percent.

To change 1/4 into a decimal, divide the numerator by the denominator. You will get 0.25. To make 1/4 into a percent, multiply the decimal by 100 or just move the decimal two places to the right. The percent is 25%. To make 1/4 into another equivalent fraction, multiply the numerator and denominator by the same number. For example, you can multiply the numerator by 2 and the denominator by 2. So, another equivalent fraction for 1/4 is 2/8.

Hope it helps :)

8 0

3 years ago

Read 2 more answers

1.)Solve the inequality. Graph the solution.

Anika [276]

Answer:

Part 1) $r\geq \sqrt[3]{-6}$

Part 2) $s>4/43$

Part 3) $z\leq6$

Part 4) $t>-7$

Part 5) $q$

Part 6) $p\geq -121/13$

Step-by-step explanation:

Part 1) $-r^{3}\leq 6$

Multiply by -1 both sides

$r^{3}\geq -6$

$r\geq \sqrt[3]{-6}$

$r\geq -1.817$

The solution is the interval -------> [-1.817,∞)

The solution in the attached figure N 1

Part 2) $-4>-43s$

rewrite

$-43s$

Multiply by -1 both sides

$43s>4$

$s>4/43$

$s>0.09$

The solution is the interval--------> (0.09,∞)

The solution in the attached figure N 2

Part 3) $z-2-6\leq-2$

combine like terms

$z-8\leq-2$

Adds 8 both sides

$z\leq-2+8$

$z\leq6$

The solution is the interval--------> (-∞,6]

The solution in the attached figure N 3

Part 4) $-2t-5$

Adds 5 both sides

$-2t$

$-2t$

Multiply by -1 both sides

$2t>-14$

Divide by 2 both sides

$t>-7$

The solution is the interval--------> (-7,∞)

The solution in the attached figure N 4

Part 5) $7(q+2)$

applying distributive property left side

$7q+14$

Subtract 14 both sides

$7q$

$7q$

Divide by 7 both sides

$q$

$q$

The solution is the interval--------> (-∞,-13)

The solution in the attached figure N 5

Part 6) $-13(p+9)\leq4$

applying distributive property left side

$-13p-117\leq4$

Adds 117 both sides

$-13p\leq4+117$

$-13p\leq 121$

Divide by -1 both sides

$13p\geq -121$

Divide by 13 both sides

$p\geq -121/13$

$p\geq -9.31$

The solution is the interval--------> [-9.31,∞)

The solution in the attached figure N 5

4 0

3 years ago

The width of a recruits 3 cm more than its length. It’s perimeter is 50 cm. Find it’s dimensions.

olga nikolaevna [1]

Answer: Length = 11 cm

Width = 14 cm

Step-by-step explanation:

Let x = Length of the rectangle.

then, width = x+ 3

Perimeter of rectangle = 2 (length +width)

Then, Perimeter = 2 (x+x+3)

= 2 (2x+3)

Since perimeter = 50 cm

$\Rightarrow\ 2(2x+3)=50$

$\Rightarrow\ 2x+3=25$ [Divide both sides by 2]

$\Rightarrow\ 2x=22\\\\\Rightarrow\ x=11$

The dimensions are :

Length = 11 cm

Width = 11+3= 14 cm

5 0

3 years ago