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Anna11 [10]
3 years ago
14

The increase in a person’s body temperature T(t), above 98. 6ºF, can be modeled by the function T (t) = StartFraction 4 t Ove

r t squared 1 EndFraction, where t represents time elapsed. What is the meaning of the horizontal asymptote for this function?.
Mathematics
1 answer:
kvv77 [185]3 years ago
3 0

The meaning of the horizontal asymptote for the given function is that;

The horizontal asymptote of y = 0 means that the person’s temperature will approach 98.6ºF as time elapses

We are told the increase in a person's body temperature above 98.6°F can be modeled by the function;

T(t) = 4t/(t² + 1)

Where;

t represents the time elapsed

Now, let us find a way to simplify the function so that t at the numerator is removed.

Thus, we will now have;

4t/(t² + 1) = 4/(t + (1/t))

To get the horizontal asymptote, we have to find the limit of the function as t approaches infinity.

Thus;

Lim t ➡ ∞ gives;

T(∞) = 4 × 1/(∞ + (1/∞))

T(∞) = 4 × 0

T(∞) = 0

This means that y = 0 is the horizontal asymptote of the function.

Thus, in conclusion The horizontal asymptote of y = 0 means that the person’s temperature will approach 98.6ºF as time elapses

Read more on horizontal asymptote at; brainly.com/question/8493280

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