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lina2011 [118]
2 years ago
8

Which venn diagram best represents the relationship between an element and a substance​

Chemistry
1 answer:
Airida [17]2 years ago
5 0

Answer:b

Explanation:b

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What protein molecules does DNA wrap around to form a nucleosome
Delvig [45]

Answer:

Histone proteins.

Explanation:

Histones are known as the special type of proteins which are +ve charged and low molecular in weight. They are highly basic proteins and containing basic amino acids such as arginine and lysine. Histones are +ve charged proteins and DNA is -ve charged in nature, due to the presence of phosphate groups in DNA backbone, histones bind with DNA very tightly and form a complex known as Nucleosome.

The Nucleosome is known as the fundamental unit of DNA packaging which is composed of an Octameric core of histone proteins (two each of histones H2A, H2B, H3, and H4) around which the double helix of DNA is wrapped.

4 0
3 years ago
How is the water in hydrothermal vents heated
yarga [219]
By hot springs, fumaroles and geysers.
6 0
3 years ago
Read 2 more answers
- How many moles of S2 are needed to produce 1.50 moles of SO2 gas? S2 + 20, ----> 2802​
matrenka [14]

Answer:

0.75 moles

Explanation:

S2 + 2O2 = 2SO2

From the reaction above,

We see that number of moles attached to S2 is 1 and number of moles attached to SO2 is 2.

Since we want to find how many moles of S2 are needed to produce 1.50 moles of SO2 gas

The answer is gotten by proportion;

Number of moles = 1/2 × 1.5 = 0.75 moles

3 0
3 years ago
Help me please i need it for homework i cant seen to solve the answer :((
strojnjashka [21]
Bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
7 0
3 years ago
alculate the standard enthalpy of formation of ethanoic acid given that the standard enthalpy of combustion for carbon is –394 k
agasfer [191]

Answer:

The standard enthalpy of formation of ethanoic acid is -484 kJ/mol.

Explanation:

C(g)+O_2(g)\rightarrow CO_2(g),\Delta H_{1, comb}=-394 kJ/mol...[1]

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l),\Delta H_{2, comb}=-286 kJ/mol..[2]

CH_3COOH(l)+2O_2(g)\rightarrow 2CO_2(g)+2H_2O(l),\Delta H_{3, comb}=-876 kJ/mol..[3]

The standard enthalpy of formation of ethanoic acid :

2C(g)+2H_2(g)+O_2(g)\rightarrow CH_3COOH, \Delta H_{4}=?..[4]

Using Hess's law to calculate :

2 × [1] + 2 × [2] - [3] = [4]

\Delta H_4=2\times (-394 kJ/mol)+2\times (-286 kJ/mol) - (-876 kJ/mol)

=\Delta H_4=-484 kJ/mol

The standard enthalpy of formation of ethanoic acid is -484 kJ/mol.

5 0
3 years ago
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