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2 years ago

A nail contains 0.10 moles of iron. How many grams of iron are in the nail?

Chemistry

1 answer:

oksano4ka [1.4K]2 years ago

4 0

Answer:

10.8

Explanation:

That's my guess, I hope you figure everything out though.

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What mass of Ca(OH)2 will be used to make 45.6g of NaOH?

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2 years ago

Calculate the magnitude and direction (i.e., the angle with respect to the positive H-axis, measured positive as counter-clockwi

r-ruslan [8.4K]

The graphics in the attachment is part of the question, which was incomplete.

Answer: Fr = 102N and angle of approximately 11°.

Explanation: From the attachment, it is observed that from the three forces acting on M, two are perpendicular. So to find them, we have to show their x- and y- axis components. From the graph:

Fx = 70+40-10 = 100

Fy = 40-20 = 20

Now, as the forces form a triangle, the totalforce is:

Fr = $\sqrt{Fx^{2} +Fy^{2} }$

Fr = $\sqrt{10400}$

Fr = ≈ 102N

To determine the angle requested, we use:

arctg H = $\frac{Fy}{Fx}$

arctg H = $\frac{20}{100}$

H = tg 0.2 ≈ 11°.

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3 years ago

The metallic radius of a potassium atom is 231 pm. What is the volume of a potassium atom in cubic meters?

Sauron [17]

1 pm = 10∧-10 cm
Therefore, 230 pm is equivalent to 2.3 ×10∧-8 cm.
Atom is in the shape of a sphere,
The volume of a sphere is given by 4/3πr³
Thus, volume of the atom = 4/3π( 2.3 ×10∧-8)³
= 4/3 (3.142 ×12.167×10∧-24
= 5.096 ×10∧-23 cm³
but 1m³= 1000000cm³
Therefore, the volume of the atom = 5.096 ×10∧-29 m³

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3 years ago

How many grams of sodium nitrate (NaNO2) will dissolve in 100g of water at 20°C?

inn [45]

88g ( so sorry if this isn’t correct )

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2 years ago

a compound has a molar mass of 129 g/mol if its empirical formula is C2H5N then what is the molecular formula

Elena-2011 [213]

Given :

A compound has a molar mass of 129 g/mol .

Empirical formula of compound is C₂H₅N .

To Find :

The molecular formula of the compound.

Solution :

Empirical mass of compound :

$M_e = ( 2 \times 12 ) + ( 5 \times 1 ) + ( 1 \times 14 )\\\\M_e = 43\ gram/mol$

Now, n-factor is :

$n = \dfrac{M}{M_e}\\\\n = \dfrac{129}{43}\\\\n = 3$

Multiplying each atom in the formula by 3 , we get :

Molecular Formula, C₆H₁₅N₃

3 0

2 years ago