Answer:
2. 181.25 K.
3. 0.04 atm.
Explanation:
2. Determination of the temperature.
Number of mole (n) = 2.1 moles
Pressure (P) = 1.25 atm
Volume (V) = 25 L
Gas constant (R) = 0.0821 atm.L/Kmol
Temperature (T) =?
The temperature can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
1.25 × 25 = 2.1 × 0.0821 × T
31.25 = 0.17241 × T
Divide both side by 0.17241
T = 31.25 / 0.17241
T = 181.25 K
Thus, the temperature is 181.25 K.
3. Determination of the pressure.
Number of mole (n) = 10 moles
Volume (V) = 5000 L
Temperature (T) = –10 °C = –10 °C + 273 = 263 K
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =?
The pressure can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
P × 5000 = 10 × 0.0821 × 263
P × 5000 = 215.923
Divide both side by 5000
P = 215.923 / 5000
P = 0.04 atm
Thus, the pressure is 0.04 atm
Answer:
Five
Explanation:
All group 15 elements have five valence electrons, but they vary in their reactivity.
multiply the number of each atom with its molecular mass. (see the periodic table)
5*12 + 12*1 = 72 gram per mole.
Or more accurately: 5*12.01078 + 12*1.007947 = 72.149264 g/mole
Well thats a pretty difficult question, I think the answer might be 4
Answer:
The molarity of the solution is: 2 M
Explanation:
We calculate the weight of 1 mol of NaOH:
Weight 1 mol NaOH= Weight Na + Weight 0 + Weight H= 23 g+16g+ 1 g= 40g/mol
The molarity is the quantity of moles in 1000ml (1 liter) of solution:
0,5liter-----40 grams NaOH
1 liter----x=(1 liter x 40 grams NOH)/0,5 liter = 80 grams NaOH
40 grams----1 mol NaOH
80 grams----X=(80 grams x 1 mol NaOH)/40 grams= 2 mol NaOH--> 2M
