What are the demensions of a rectangle if the perimiter is 20 and the area is 24
1 answer:
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Answer:
<h2> 63° or 173°</h2>Step-by-step explanation:
You didn't specify where the point P is so there are two posibilites:
1.
P₁Z is dividing angle OZQ
then:
m∠P₁ZQ = m∠OZQ - m∠OZP₁ = 125° - 62° = 63°
2.
P₂Z is outside angle OZQ
then
m∠P₂ZQ = 360° - (m∠OZQ + m∠OZP₂) = 360° - (125° + 62°) = 173°
