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s2008m [1.1K]
3 years ago
14

A recipe calls for 3/4 of a cup of flour to make 5/8 of a pound of bread

Mathematics
1 answer:
schepotkina [342]3 years ago
8 0

Answer:

\huge\boxed{\sf 1 \ pound \ of \ dough = 1\frac{1}{5}  \ cup \ of \ flour}

Step-by-step explanation:

\displaystyle \underline{Given \ that:}\\\\\frac{5}{8} \ pound \ of \ dough = \frac{3}{4} \ cup\ of \ flour\\\\Multiply \ 8 \ to \ both \ sides\\\\5 \ pounds \ of \ dough = \frac{3}{4} \times 8 \ cup \ of \ flour\\\\5 \ pounds \ of \ dough = 3 \times 2 \ cup \ of \ flour\\\\5 \ pounds \ of \ dough = 6 \ cups \ of \ flour\\\\Divide \ both \ sides \ by \ 5\\\\1 \ pound \ of \ dough = \frac{6}{5}  \ cup \ of \ flour\\\\\boxed{1 \ pound \ of \ dough = 1\frac{1}{5}  \ cup \ of \ flour}\\\\

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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I need help in partial fraction!! With simple explaination would be nice!
WITCHER [35]
\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}

The degree of the numerator (4) is larger than the degree of the denominator (3), so first you need to divide. (Added screenshot of long division procedure.)

\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x-\dfrac{4x^2-17x+10}{x(x^2-3)}

Now the second term can be decomposed into partial fractions.

\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1}x+\dfrac{r_2x+r_3}{x^2-3}
\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1(x^2-3)+x(r_2x+r_3)}{x(x^2-3)}
4x^2-17x+10=r_1(x^2-3)+x(r_2x+r_3)
4x^2-17x+10=(r_1+r_2)x^2+r_3x-3r_1
\implies\begin{cases}r_1+r_2=4\\r_3=-17\\-3r_1=10\end{cases}\implies r_1=-\dfrac{10}3,r_2=\dfrac{22}3,r_3=-17=-\dfrac{51}3
\implies\dfrac{4x^2-17x+10}{x(x^2-3)}=-\dfrac{10}{3x}+\dfrac{22x-51}{x^2-3}

So

\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x+\dfrac{10}{3x}-\dfrac{22x-51}{x^2-3}

3 0
3 years ago
×/5 + 9 = 4 please solve the equation
iren [92.7K]
Assuming you are solving for x

do the opposite of PEMDAS. Isolate the x. Because of equal sign, what you do to one side, you do to the other.

x/5 + 9 = 4

x/5 + 9 (-9) = 4 (-9)

x/5 = 4 - 9

x/5 = -5

x/5(5) = -5(5)

x = -5(5)

x = -25

-25 is your answer for x

hope this helps
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Step-by-step explanation:

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