Answer:
Find a polynomial function whose graph passes through (6,13), (9,-11), (0,5)
1 Answers
Assuming a quadratic, we have that
y = ax^2 + bx + c
Since (0,5) is on the graph, c =5
And we have the remaining system
a(9)^2 + b(9) + 5 = -11
a(6)^2 + b(6) + 5 = 13 simplify
81a + 9b = -16 multiply through by 6 ⇒ 486a + 54b = - 96 (1)
36a + 6b = 8 multiply through by -9 ⇒ -324a -54b = -72 (2)
Add (1) and (2)
162a = -168
a = -28/27
To find b we have
36 (-28/27) + 6b = 8
-112/3 + 6b = 8
⇒ b = 68/9
The function is
y = - (28/27)x^2 + (68/9)x + 5
Answer:
Step-by-step explanation:
.............................. where is the table
-43
-44
-45.
-43 + -45 is -88
Answer:
65000
Step-by-step explanation:
Just round the number
Answer:
x = -12
Step-by-step explanation:
Set logs up on both sides-
log 16^x = log 64^x+4
The variable goes behind because of the exponent log <em>property</em> (exponents are permitted to go behind the log to multiply)-
x * log 16 = x + 4 * log 64
Divide both logs out-
log 64/log 16 = 1.5
Simplify-
x = x+4(1.5)
1.5x + 6 = x
Remove 1.5-
1 - 1.5 = -.5x
Simplify-
-.5x = 6
Divide both sides-
6/-.5x = -12
Hence, the answer would be -12
