Olly plans to purchase a watch with an original price of $78. The

2 answers:

4 0

Olly will pay 15.6 because 78 - 15% but you add your 5 percent that’s 20 percent so just do 78 - 20% and you will get 15 dollars and six cents

kozerog [31]2 years ago

3 0

$62.40

When adding up all the discounts, it is 20%. In order to figure out how much he has to pay, you do 78 times 0.80 (since you’re only paying 80% of the money for the shirt). This gets you 62.4 which is 62.40 in cash.

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Find the 11th term of the following geometric sequence.<br> 2, 8, 32, 128, ...

Hitman42 [59]

The 11th term is 2, 095, 152

Explanation:
This is a geometric sequence, since each term after the first is obtained by multiplying a common ratio,
r
.
The common ratio is
4
. The first term,
a
, is
2
. The number of terms,
n
is
11
.
We use the formula
t
n
=
a
×
r
n
−
1
to determine the nth term in a geometric sequence.
t
11
=
2
×
4
11
−
1
t
11
=
2
,
095
,
152
Hopefully this helps!

4 0

3 years ago

A) Using your equation from step 2d, estimate the GPA of a student who studies for 15 hours a

hram777 [196]

Answer:

The predicted GPA is then y = 0.149(15) + 0.89 = 3.1

Step-by-step explanation:

Although you don't specifically say so, the equation you provide here is probably a "best fit" equation based upon data: GPA versus the number of hours of study per week.

y = 0.149x + 0.89 and the number of study hours of interest is 15.

6 0

2 years ago

In variables estimation sampling, the sample standard deviation is used to calculate the?

Nikitich [7]

The sample standard deviation is used to calculate the determine the spread of estimates for a set of observations (i.e., a data set) from the mean (average or expected value).

<h3>What is sample standard deviation?</h3>

The spread of a data distribution is measured by standard deviation. The average distance between each data point and the mean is measured.

The sample standard deviation (s) is a measurement of the variation from the expected values and is equal to the sample variance's square root.

where

s = sample standard deviation

N = the number of observations

$xi$ = the observed values of a sample item