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mel-nik [20]
3 years ago
7

Determine which ordered pair is a solution of y=8x.

Mathematics
2 answers:
MAXImum [283]3 years ago
7 0
Y = 8x
y = 8(2)
y = 16
(x, y) = (2, 16)

The answer is D.
MrRissso [65]3 years ago
6 0

we know that

If the ordered pair is a solution of the equation, then the ordered pair must satisfied the equation

we will proceed to solve each case to determine the solution of the problem

we have

y=8x -------> equation 1

<u>case a)</u> (0,8)

x=0\\y=8

For x=0

substitute the value of x in the equation 1 and then compare the values of y

y=8*0=0

so

0\neq 8

The ordered pair case a) is not solution

<u>case b)</u> (-1,8)

x=-1\\y=8

For x=-1

substitute the value of x in the equation 1 and then compare the values of y

y=8*(-1)=-8

so

-8\neq 8

The ordered pair case b) is not solution

<u>case c)</u> (1.5,10)

x=1.5\\y=10

For x=1.5

substitute the value of x in the equation 1 and then compare the values of y

y=8*1.5=12

so

12\neq 10

The ordered pair case c) is not solution

<u>case d)</u> (2,16)

x=2\\y=16

For x=2

substitute the value of x in the equation 1 and then compare the values of y

y=8*2=16

so

16=16

The ordered pair case d) is a solution

therefore

<u>the answer is</u>

(2,16)

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A and E are corresponding angles so A=E
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2 years ago
write an equation for the line that passes through the given point and has the given slope m (4,-5);m= -1/4
EastWind [94]

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{y = -1/4x - 4}

-------------------------------------------------------------------------------------------------------------

Given: \textsf{Slope = -1/4, Point through = (4, -5)}

Find:  \textsf{Equation for the line that passes through the given point}

Solution: In order to get the equation, we need to first use the point-slope form to help us sort out our information and then we solve for y.

<u>Plug in the values</u>

  • \textsf{y - y}_1\textsf{ = m(x - x}_1\textsf{)}
  • \textsf{y - (-5) = -1/4(x - 4)}

<u>Simplify and solve for y</u>

  • \textsf{y + 5 = -1/4(x - 4)}
  • \textsf{y + 5 = -1/4x + 1}
  • \textsf{y + 5 - 5 = -1/4x + 1 - 5}
  • \textsf{y = -1/4x - 4}

Therefore, the final answer would be that the equation that has a slope of -1/4 and passes through (4, -5) is y = -1/4x - 4.

5 0
2 years ago
When is the best time to use square roots to solve a quadratic? Choose the one BEST
blondinia [14]

Answer: D, When the constants are perfect squares.

Step-by-step explanation:

the “best” method whenever the quadratic equation only contains x2 terms. That implies no presence of any x term being raised to the first power somewhere in the equation.

Hopefully this helps!

8 0
2 years ago
I need help please anybody
erma4kov [3.2K]
Answer: area= 4.7

Area=pi*r^2=3.14*1.5=4.71=4.7 (nearest tenth)
6 0
2 years ago
Hey everyone !
zhuklara [117]

Answer:

The measure of the largest angle is 120°

Step-by-step explanation:

<em>Lets explain how to find the measure of an angle from the length of the </em>

<em>sides of the triangle</em>

- We can do that by using the cosine rule

- If the three angles of the triangle are A , B , C, then the side opposite

 to angle A is BC , the side opposite to angle B is AC and the side

 opposite to angle C is AB, So to find measure of angle A use the rule

 cos(A)=\frac{(AB)^{2}+(AC)^{2}-(BC)^{2}}{2(AB)(AC)}

<em>Lets solve the problem</em>

- Assume that the triangle is ABC where AB = 14 cm , BC = 10 cm and

 AC = 6 cm

- We need to find the measure of the largest angle

- The largest angle is opposite to the longest side

∵ The longest side is AB

∴ The largest angle is C

By using the rule above

∴ cos(C)=\frac{(AC)^{2}+(BC)^{2}-(AB)^{2}}{2(AC)(BC)}

∵ AB = 14 cm , BC = 10 cm , AC = 6 cm

∴ cos(C)=\frac{(6)^{2}+(10)^{2}-(14)^{2}}{2(6)(10)}

∴ cos(C)=\frac{36+100-196}{120}

∴ cos(C)=\frac{-60}{120}=-0.5

∴ cos(C) = -0.5 ⇒ that means angle C is obtuse angle

∴ m∠C = cos^{-1}(-0.5)=120

* <em>The measure of the largest angle is 120°</em>

8 0
2 years ago
Read 2 more answers
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