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MaRussiya [10]
4 years ago
10

Pumping apparatus driver/operators must be familiar with the different types of nozzles carried on their apparatus. How would a

particular type of nozzle being used affect the hydraulic calculations that must be performed by the driver/operator?
Physics
1 answer:
Vadim26 [7]4 years ago
5 0

Answer:

Each type of nozzle has its discharge pressure and optimum flow rate which affect the hydraulic calculations.

Explanation:

There are different types of nozzles used for pumping operation. Each type of nozzle has its discharge pressure and optimum flow rate. And in hydraulic calculations, various nozzle parameters (such as discharge pressure and optimum flow rate) are needed. Therefore, the capabilities of these nozzles to generate the proper fluid volume and pressure must be carefully understood.

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An astronaut in an inertial reference frame measures a time interval Δt between her heartbeats. What will observers in all other
Reika [66]

Answer:

It will be more than deta t

Explanation:

Because

deta t' = န deta t

But န= 1/√ (1 - v²/c²

So the observers in all the initial frames will be more than deta t

3 0
4 years ago
The driver of a car traveling at 31.3 m/s applies the brakes and undergoes a constant deceleration of 1.6 m/s2.How many revoluti
lisov135 [29]

Answer:

R=156.99\operatorname{Re}vs

Explanation: The equations used are as follows:

\begin{gathered} x(t)=x_o+v_ot+\frac{1}{2}at^2\Rightarrow(1) \\ v(t)=v_o+at\Rightarrow(2) \end{gathered}

By using equation (2), the time needed for the car to come to rest is calculated as follows:

\begin{gathered} v(t)=(31.3ms^{-1})_{}+(-1.6ms^{-2})t=0 \\ t=\frac{31.3ms^{-1}}{1.6ms^{-2}}=19.56s \\ t=19.563s \end{gathered}

By using equation (1), The total distance traveled in that time would be as:

\begin{gathered} x(19.563s)=_{}(31.3ms^{-1})\cdot(19.563s)+\frac{1}{2}(-1.6ms^{-2})\cdot(19.563s)^2\Rightarrow(1) \\ x(19.563s)=612.31-306.17=306.14m \\ \therefore\Rightarrow \\ x(19.563s)=306.14m \end{gathered}

The revolutions taken by the tire before the car comes to rest would be:

\begin{gathered} C=2\pi\cdot(0.31m)=1.95m \\ R=\frac{x(19.563s)}{C}=\frac{306.14m}{1.95m}=156.99\operatorname{Re}v \\ R=156.99\operatorname{Re}vs \end{gathered}

3 0
2 years ago
The 20 g bullet is traveling at 400 m/s when it becomes embedded in the 2 -kg stationary block. Determine the distance the block
Marina CMI [18]

Answer:

The block+bullet system moves 4 m before being stopped by the frictional force.

Explanation:

Using the law of conservation of llinear momentum and the work energy theorem, we can obtain this.

According to Newton's second law of motion

Momentum before collision = Momentum after collision

Momentum before collision = (0.02×400) + 0 (stationary block)

Momentum before collision = 8 kgm/s

Momentum after collision = (2+0.02)v

8 = 2.02v

v = 3.96 m/s.

According to the work-energy theorem,

The kinetic energy of the block+bullet system = work done by Friction to stop the motion of the block+bullet system

Kinetic energy = (1/2)(2.02)(3.96²) = 15.84 J

Work done by the frictional force = F × (distance moved by the force)

F = μmg = 0.2(2.02)(9.8) = 3.96 N

3.96d = 15.84

d = (15.84/3.96) = 4 m

5 0
3 years ago
Define equilibrium and explain first condition of equilibrium. Pease make it fast...
Semenov [28]

Answer:

First Condition of Equilibrium

For an object to be in equilibrium, it must be experiencing no acceleration. This means that both the net force and the net torque on the object must be zero. Here we will discuss the first condition, that of zero net force. ... Fnet=0 F net = 0.

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4 years ago
PLEASE HELP IVE BEEN STUCK ON THIS FOR 3HOURS!
Anika [276]

Answer:

The river bank can expand due to the water breaking apart which can cause sediment to move and change/erode

5 0
4 years ago
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