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3 years ago

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An object 4cm high is placed 15 cm from a convex lens of focal length 18cm. Draw a ray diagram and find the position, size, and

nature of the image

1 answer:

Nataly [62]3 years ago

3 0

Answer:

what I don't no really????

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A gun has a muzzle speed of 80 meters per second. What angle of elevation should be used to hit an object 180 meters away? Negle

olga55 [171]

Knowing the initial velocity and angle, the horizontal range formula is given by R= V^2sin(2teta) / g, so we can get
sin(2teta)=Rg/V^2
sin(2teta)= (180 x 9.8)/ 80^2= 0.27, sin(2teta)=0.27, 2teta=arcsin(0.27)=15.66, so teta=15.66/2

teta=7.83°

5 0

4 years ago

Read 2 more answers

A 55 kg skater at rest on a frictionless rink throws a 3 kg ball, giving the ball a velocity of 8 m/s. What is the velocity of t

KengaRu [80]

Answer:

The velocity will be v1 = 0.58[m/s]

Explanation:

This problem can be solved by the law of conservation of the moment, which explains that the moment of a system remains constant because there are no external forces acting on it.

We have the following initial data:

m1 = mass of the skater = 55 [kg]

m2 = mass of the ball = 3 [kg]

v2 = velocity of the ball = 8 [m/s]

Therefore:

$m_{1}*v_{1}+m_{2}*v_{2}=m_{1}*v_{1}+m_{2}*v_{2}\\(50*0)+(3*0)=(50*v_{1})+(3*8)\\50+3-24=50*v_{1}\\v_{1}= 0.58[m/s]$

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3 years ago

A kg object has 400 j of potential energy. Find how high off the groumd the object is

blondinia [14]

Potential energy = mgh
Energy, U = 400J
g = 10m/s^2
m = A kg
h = U ÷ mg
= 400÷10A
= 40÷A

mass is not given

6 0

3 years ago

A potentiometer wire of length 1m and resistance 2Ω is connected in series with a variable resistance and 2V accumulator of negl

cluponka [151]

Answer:

wire

Explanation:

we need insulator to conduct the experiment

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3 years ago

ASAP PLEASE! WILL GIVE BRAINLIEST ANSWER! The pictures below show the wavelengths and intensities of electromagnetic radiations

rjkz [21]

As per Weins displacement law the wavelength of light for which we get the peak of the graph is always inversely proportional to the temperature.

So we can say

$/lambda = \frac{b}{T}$

So here if temperature becomes more cool then wavelength will increase

here we know that

$\lambda_1 = 8500 A^o$

$\lambda_2 = 6000 A^o$

$\lambda_3 = 3500 A^o$

It means the hottest star out of all three is star 3

and coolest star is star 1

now if we star 2 becomes cooler then it means its temperature will go near to star 1 and hence it will more look like to star 1.

So correct answer is

it will look more like Star 1

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3 years ago