Knowing the initial velocity and angle, the horizontal range formula is given by R= V^2sin(2teta) / g, so we can get
sin(2teta)=Rg/V^2
sin(2teta)= (180 x 9.8)/ 80^2= 0.27, sin(2teta)=0.27, 2teta=arcsin(0.27)=15.66, so teta=15.66/2
teta=7.83°
Answer:
The velocity will be v1 = 0.58[m/s]
Explanation:
This problem can be solved by the law of conservation of the moment, which explains that the moment of a system remains constant because there are no external forces acting on it.
We have the following initial data:
m1 = mass of the skater = 55 [kg]
m2 = mass of the ball = 3 [kg]
v2 = velocity of the ball = 8 [m/s]
Therefore:
![m_{1}*v_{1}+m_{2}*v_{2}=m_{1}*v_{1}+m_{2}*v_{2}\\(50*0)+(3*0)=(50*v_{1})+(3*8)\\50+3-24=50*v_{1}\\v_{1}= 0.58[m/s]](https://tex.z-dn.net/?f=m_%7B1%7D%2Av_%7B1%7D%2Bm_%7B2%7D%2Av_%7B2%7D%3Dm_%7B1%7D%2Av_%7B1%7D%2Bm_%7B2%7D%2Av_%7B2%7D%5C%5C%2850%2A0%29%2B%283%2A0%29%3D%2850%2Av_%7B1%7D%29%2B%283%2A8%29%5C%5C50%2B3-24%3D50%2Av_%7B1%7D%5C%5Cv_%7B1%7D%3D%200.58%5Bm%2Fs%5D)
Potential energy = mgh
Energy, U = 400J
g = 10m/s^2
m = A kg
h = U ÷ mg
= 400÷10A
= 40÷A
mass is not given
Answer:
wire
Explanation:
we need insulator to conduct the experiment
As per Weins displacement law the wavelength of light for which we get the peak of the graph is always inversely proportional to the temperature.
So we can say

So here if temperature becomes more cool then wavelength will increase
here we know that



It means the hottest star out of all three is star 3
and coolest star is star 1
now if we star 2 becomes cooler then it means its temperature will go near to star 1 and hence it will more look like to star 1.
So correct answer is
it will look more like Star 1