Answer:
Classification
Explanation:
Building a machine learning solution that can predict the success of a student in completing a college degree is a binary problem. There are two possible answer: success or not success.
This brings us to a supervised machine learning problem, where one trains the technique with labeled data whether it is a success or not. Since the target variable is discrete (not continuous), classification technique has to be used.
Have them post more positive outcomes and help them understand that what they post stays there forever
To start combining, select the Merge Mode option on the Comparison tab. Next, click the button next to the line you wish to merge in order to replace content from the right pane with content from the left pane.
<h3>How is boundary layer thickness calculated?</h3>
- Where x is a position parallel to the wall, y is a coordinate normal to the wall, v is a (small) viscosity, u = (u, v) is the velocity, is the vorticity, and so on. The boundary conditions are as follows: u(x,y = +,t) = U, and u(x,y = 0,t) = 0.
- To gauge the overall pressure, a vertically sliding Pitot tube is employed. So that the growth of the boundary layer in the flow direction can be seen, the total pressures can be recorded at various distances from the plate surface. Static pressure is gauged at a different measurement location.
- To start combining, select the Merge Mode option on the Comparison tab. Next, click the button next to the line you wish to merge in order to replace content from the right pane with content from the left pane. Alternatively, you can pick a discrepancy and choose Replace Content from the Comparison tab.
To learn more about Boundary conditions refer to:
brainly.com/question/23802083
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Answer:
import java.util.Scanner;
class Main {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
System.out.print("Enter a decimal value (0 to 15): ");
int num = scan.nextInt();
scan.close();
if (num < 0 || num >15) {
System.out.printf("%d is an invalid input\n", num);
} else {
System.out.printf("The hex value is %X\n", num);
}
}
}
Explanation:
Hopefully this example will get you going for the other assignments.
It gains purchasing power. Less money in circulation = more value.
