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3 years ago

Help help help me please

Mathematics

1 answer:

spayn [35]3 years ago

8 0

Answer:

$A$ ≈ $80.03$

Step-by-step explanation:

I used the equation $A=$ π $r(r+h^{2}+r^{2})$ to find the surface area

i hope this helps

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HurRRy PleAsE HeLp ME MarKinG BraInLiESt

Nastasia [14]

Answer:

15/4

Step-by-step explanation:

Fractions are basically division problems you divide the nominator by the denominator

3 0

3 years ago

HELLOOOO HELP PLEASE

MA_775_DIABLO [31]

Answer:

$2*log(x)+log(y)$

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

<em>Logarithm of a power</em>:

$log_ba^c=c*log_ba$

So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: $log_ba=x\implies b^x=a$

Now if we raise both sides to the power of c, we get the following equation: $(b^x)^c=a^c$

Using the exponential identity: $(x^a)^c=x^{a*c}$

We get the equation: $b^{xc}=a^c$

If we convert this back into logarithmic form we get: $log_ba^c=x*c$

Since x was the basic logarithm we started with, we substitute it back in, to get the equation: $log_ba^c=c*log_ba$

Now the second logarithmic property you need to know is

<em>The Logarithm of a Product</em>:

$log_b{ac}=log_ba+log_bc$

Now for a quick proof, let's just say: $x=log_ba\text{ and }y=log_bc$

Now rewriting them both in exponential form, we get the equations:

$b^x=a\\b^y=c$

We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

$b^x*b^y=a*c$

Using the exponential identity: $x^{a}*x^b=x^{a+b}$ , we can rewrite the equation as:

$b^{x+y}=ac$

taking the logarithm of both sides, we get:

$log_bac=x+y$

Since x and y are just the logarithms we started with, we can substitute them back in to get: $log_bac=log_ba+log_bc$

Now let's use these identities to rewrite the equation you gave

$log(x^2y)$

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

$log(x^2)+log(y)$

Now using the logarithm of a power to rewrite the log(x^2) we get:

$2*log(x)+log(y)$

3 0

1 year ago

Nitric acid (specific gravity 1.42) costs $51.95 per liter. A student spills 5.112 kg of nitric acid in the laboratory, what is

Leno4ka [110]

Answer:

The cost of wasted nitric acid is $187.02

Step-by-step explanation:

Since it is given that specific gravity of Nitric Acid is 1.42 Thus the density of nitric acid is

$\rho _{acid}=S.G\times \rho _{water}\\\\\\\rho_{acid}=1.42\times 1\frac{g}{cm^3}\\\\\rho_{acid}=1.42g/cm^3$

Now from the basic relation of mass volume and density we have

$\rho =\frac{Mass}{Volume}\\\\\therefore Volume=\frac{Mass}{\rho }$

Since the mass of the nitric acid is given to be 5.112 kg = 5112 grams

Thus the volume of nitric acid is

$Volume=\frac{5112}{1.42}=3600cm^3$

Now we know that 1000 cubic centimeters euals 1 litrer

Thus the calculated volume in liters is

$V_{liters}=\frac{3600}{1000}=3.6Liters$

Thus the cost of acid spilled equals

$Cost=3.6\times 51.95=187.02$

5 0

3 years ago

26.45+4.79+120.02-3.20=

viva [34]

The answer to your question is = 148.06

6 0

3 years ago

Read 2 more answers

Which statement is true?

kobusy [5.1K]

A all squares have the sides

6 0

2 years ago