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Kitty [74]
2 years ago
11

I need it ASAP, Questions are attached as a photo

Mathematics
1 answer:
ELEN [110]2 years ago
5 0

Answer:

8- 26 cm

7- 85 cm^2

1-23 cm

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3. Theresa has 20 coins that are dimes and quarters. Together
KiRa [710]

Answer:

  • 15 dimes
  • 5 quarters

Step-by-step explanation:

Let q represent the number of quarters Theresa has. Then the value of her coins is ...

  0.25q + 0.10(20 -q) = 2.75

  0.15q = 0.75 . . . . . . . . . subtract 2.00, collect terms

  q = 0.75/0.15 = 5

Theresa has 5 quarters and 15 dimes.

3 0
3 years ago
What value in Vertex Form moves the graph up?
Leno4ka [110]
Changing from negative to positive
6 0
2 years ago
Find the total surface area of this cone.<br> leave your answer in terms of pi<br> R=3<br> L=4
Yuliya22 [10]

Answer:

total surface area of cone is πr (r+l)

22/7 x 3 (3+4)

22/7*3 (7)

22 x 3 ( as 7 that was divided by 22 was cut out with 7 in the bracket)

hence,

TSA of cone = 66pi

8 0
2 years ago
A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

We dont know the true proportion, so we use \pi = 0.5, which is when we are are going to need the largest sample size.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.04\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.04}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2

n = 600.25

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.02\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.02}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.02})^2

n = 2401

The minimum sample size is 2401.

4 0
3 years ago
Mia discovered that if she takes half her age and adds 3, it produces the same results as taking one-fourth of her age and addin
Vikentia [17]

See https://web2.0calc.com/questions/help_29833.

5 0
3 years ago
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